ios - 将模型发布到委托(delegate) View 的正确方法？

Question

我有一个 UITableViewController，它提供一个字符串数组作为数据源:

import UIKit

class ItemsViewController: UITableViewController {

    let items = [
        "Bob",
        "Joe",
    ]

    @IBAction
    func unwindToSegue(segue: UIStoryboardSegue) {

    }

    override func numberOfSectionsInTableView(tableView: UITableView) -> Int {
        return 1
    }

    override func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
        return items.count
    }

    override func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
        let cell = tableView.dequeueReusableCellWithIdentifier("Item", forIndexPath: indexPath) as UITableViewCell

        cell.textLabel.text = items[indexPath.row]

        return cell
    }

}

我现在添加了第二个带有 UIViewController 的场景，当用户通过 show segue 点击 UITableCell 时，它会被激活。 p>

我现在想把分配给以前的 UITableCell 的字符串插入到 ItemViewController 中:

import UIKit

class ItemViewController: UIViewController {

    @IBOutlet
    weak var nameLabel: UILabel!

    override func viewDidLoad() {
        super.viewDidLoad()
    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
    }

    override func override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
        //var name = segue.someMethodHowIGetTheDataAssignedToTableCell
        //nameLabel.text = name
    }

}

如何将分配给单个 TableCell 的模型(在本例中为字符串)传递给新的 ItemViewController？

Answer 1

像这样。只需添加一个从 ItemViewController 返回到 ItemsViewController 的返回推送 segue。以后将它们命名为不那么相似:-)

import UIKit

class ItemsViewController: UITableViewController {

    let items = [
        "Bob",
        "Joe",
    ]

    @IBAction
    func unwindToSegue(segue: UIStoryboardSegue) {

    }

    override func numberOfSectionsInTableView(tableView: UITableView) -> Int {
        return 1
    }

    override func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
        return items.count
    }

    override func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
        let cell = tableView.dequeueReusableCellWithIdentifier("Item", forIndexPath: indexPath) as UITableViewCell

        cell.textLabel.text = items[indexPath.row]

        return cell
    }

//Passing details to detail VC
    override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {

            let indexPath = self.tableView.indexPathForSelectedRow()
            let theDestination = (segue.destinationViewController as ItemViewController)
            theDestination.itemName = items[indexPath!.row]
    }

}

import UIKit

class ItemViewController: UIViewController {

    @IBOutlet  weak var nameLabel: UILabel!

var itemName = ""

    override func viewDidLoad() {
        super.viewDidLoad()

        nameLabel.text = itemName
    }

}