gpt4 book ai didi

javascript - 使用单选按钮来计算测验的分数

转载 作者:行者123 更新时间:2023-11-28 07:13:16 26 4
gpt4 key购买 nike

我正在尝试使用单选按钮制作一个简单的 Javascript 测验。每个问题和选项都应存储在一个数组中,并使用 getElementById() 动态替换问题。我一直在尝试为单选按钮分配值,以便我可以在最后显示分数。

我是 javascript 新手,这是我正在从事的第一个项目。

这是我到目前为止所拥有的:

var questionsArray = new Array;
questionsArray[0] = ["1. Who is the president of the US?"];
questionsArray[1] = ["2. What is the capital city of France?"];
questionsArray[2] = ["3. What is your favorite food?"];
var choicesArray = new Array();
choicesArray[0] = ["Lebron James", "Barack Obama", "George Bush"];
choicesArray[1] = ["Nairobi", "London", "Paris"];
choicesArray[2] = ["Pizza", "Sushi", "Pasta"];
var i = 0;
var theScore = 0;

function btnOnclick() {
var radElement = document.form1.options;
var showDiv = document.getElementById("questionsDiv");
showDiv.className = "showClass";
document.getElementById("next").value = "Next";
while(i < questionsArray.length && i < choicesArray.length) {
var currQues = questionsArray[i];
var option1 = choicesArray[i][0];
var option2 = choicesArray[i][1];
var option3 = choicesArray[i][2];
i++;
document.getElementById("question").innerHTML = currQues;
document.getElementById("choice1").innerHTML = option1;
document.getElementById("choice2").innerHTML = option2;
document.getElementById("choice3").innerHTML = option3;
return true
}
if(questionsArray[0] && radElement[1].checked == true) {
theScore += 10
} else {
theScore += 0
}
if(questionsArray[1] && radElement[2].checked == true) {
theScore += 10
} else {
theScore += 0
}
if(questionsArray[2] && radElement[1].checked == true) {
theScore += 10
} else {
theScore += 0
}
alert(theScore)
}

function bodyOnload() {
var hideDiv = document.getElementById("questionsDiv");
hideDiv.className = "hideClass";
document.getElementById("next").value = "Start Quiz"
}
.hideClass{
display: none;
}

.showClass{
display: block;
}
<body onload="bodyOnload()">
<h1>QUIZ</h1>
<div id="questionsDiv">
<form name="form1">
<p id="question" class="showQuestion"></p>
<tr>
<span id="choice1"></span>
<td>
<input type="radio" id="radio1" value="0" name="options" />
</td>
<td>
<span id="choice2"></span>
<input type="radio" id="radio2" value="0" name="options" />
</td>
<td>
<span id="choice3"></span>
<input type="radio" id="radio3" value="0" name="options" />
</td>
</tr>
</div>
<br />
<br />
<hr>
<tr>
<td>
<input type="button" id="next" value="Next" name="nextButton" onclick="btnOnclick()"/>
</td>
</tr>
</form>
</body>

最佳答案

考虑将您的答案构建为对象数组,如下所示:

choicesArray[2] = [{
text: "Pizza",
correct: true
}, {
text: "Pasta",
correct: false
}, {
text: "Sushi",
correct: false
}];

然后,如果选择了radio2,则检查答案数组中的第二项以查看其是否正确,如下所示:

// use index 1 for the second choice in the list.
if(choicesArray[2][1].correct === true) {
//it's right!
} else {
//it's wrong...
}

在实现此功能之前,显然您还有很长的路要走,但这是我的第一个建议。

您可以更进一步(我愿意!),将问题和答案放在一起以便于引用:

var question = {
questionText: 'What is your favorite food?',
answers: [{
answerText: "Pizza",
correct: true
}, {
answerText: "Pasta",
correct: false
}, {
answerText: "Sushi",
correct: false
}]
};

然后您可以访问如下内容:

var currentQuestionIndex = 1; //or whatever it is

var questionText = questionsArray[currentQuestionIndex].questionText;

var answer1 = questionsArray[currentQuestionIndex].answers[0].answerText;
var answer1isCorrect = questionsArray[currentQuestionIndex].answers[0].correct;

var answer2 = questionsArray[currentQuestionIndex].answers[1].answerText;
var answer2isCorrect = questionsArray[currentQuestionIndex].answers[1].correct;

var answer3 = questionsArray[currentQuestionIndex].answers[2].answerText;
var answer3isCorrect = questionsArray[currentQuestionIndex].answers[2].correct;

此外,在向数组添加项目时不需要如此明确。它使您的代码变得脆弱。考虑使用push():

var questionsArray = [];

questionsArray.push({
questionText: 'What is your favorite food?',
answers: [{
answerText: "Pizza",
correct: true
}, {
answerText: "Pasta",
correct: false
}, {
answerText: "Sushi",
correct: false
}]
});

关于javascript - 使用单选按钮来计算测验的分数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31093396/

26 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com