C++ 清除 wstring

Question

我的问题是，以前用于字符串的方法都不能用于 wstring。所以我问我如何才能轻松清除 wstring 以达到美学目的。

我现在的代码:

    while (!foundRightOne)
    {
        wstring cTitle;
        ForegroundWindow = GetForegroundWindow();
        cout << "FRGW  " << ForegroundWindow << endl;

        int len = GetWindowTextLengthW(ForegroundWindow) + 1;
        wchar_t * windowTitle = new wchar_t[len];
        GetWindowTextW(ForegroundWindow, windowTitle, len);
        title += windowTitle;
        // OUTPUT
        cTitle = L"Title: ";
        cTitle += title;
        wcout << cTitle << endl;
        cTitle = ' ';
        //OUTPUT
        keyPress = getchar();
        system("CLS");
        if (keyPress == 'y' || keyPress == 'Y')
        {
            foundRightOne = true;
        }

    }

基本上它会在我按下 y 或 Y 时循环，当我看到正确的 cTitle 并在 ~20 cycles cTitle 被最后一个循环中的文本填满。

Answer 1

std::wstring::clear 应该可以工作，因为它和 std::string 都是 std::basic_string。查看std::basic_string如果您遇到问题，请提供文档。

#include <iostream>

int main()
{
    std::string regularString("regular string!");
    std::wstring wideString(L"wide string!");

    std::cout << regularString << std::endl << "size: " << regularString.size() << std::endl;
    std::wcout << wideString << std::endl << "size: " << wideString.size() << std::endl;

    regularString.clear();
    wideString.clear();

    std::cout << regularString << std::endl << "size: " << regularString.size() << std::endl;
    std::wcout << wideString << std::endl << "size: " << wideString.size() << std::endl;
}

输出:

regular string!
size: 15
wide string!
size: 12

size: 0

size: 0

这是一个 ideone链接到该代码。