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C++/openCV : cvConvert returns null

转载 作者:行者123 更新时间:2023-11-28 07:10:50 26 4
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我发现了一个用 C++ 编写的代码,它可以找出两个图像之间的差异。它正常加载图像,但在

cvConvert(img1_temp, img1); 

img1 保持为 NULL,最终结果(我打印的结果)为 nan。我使用的输入图像是 png。知道为什么会这样吗?

int main(int argc, char** argv)
{
if(argc!=3)
return -1;

// default settings
double C1 = 6.5025, C2 = 58.5225;

IplImage
*img1=NULL, *img2=NULL, *img1_img2=NULL,
*img1_temp=NULL, *img2_temp=NULL,
*img1_sq=NULL, *img2_sq=NULL,
*mu1=NULL, *mu2=NULL,
*mu1_sq=NULL, *mu2_sq=NULL, *mu1_mu2=NULL,
*sigma1_sq=NULL, *sigma2_sq=NULL, *sigma12=NULL,
*ssim_map=NULL, *temp1=NULL, *temp2=NULL, *temp3=NULL;


/***************************** INITS **********************************/
img1_temp = cvLoadImage(argv[1]);
img2_temp = cvLoadImage(argv[2]);

if(img1_temp==NULL || img2_temp==NULL)
return -1;

int x=img1_temp->width, y=img1_temp->height;
int nChan=img1_temp->nChannels, d=IPL_DEPTH_32F;
CvSize size = cvSize(x, y);
img1 = cvCreateImage( size, d, nChan);
img2 = cvCreateImage( size, d, nChan);

cvConvert(img1_temp, img1);
cvConvert(img2_temp, img2);
cvReleaseImage(&img1_temp);
cvReleaseImage(&img2_temp);

img1_sq = cvCreateImage( size, d, nChan);
img2_sq = cvCreateImage( size, d, nChan);
img1_img2 = cvCreateImage( size, d, nChan);

cvPow( img1, img1_sq, 2 );
cvPow( img2, img2_sq, 2 );
cvMul( img1, img2, img1_img2, 1 );

mu1 = cvCreateImage( size, d, nChan);
mu2 = cvCreateImage( size, d, nChan);

mu1_sq = cvCreateImage( size, d, nChan);
mu2_sq = cvCreateImage( size, d, nChan);
mu1_mu2 = cvCreateImage( size, d, nChan);


sigma1_sq = cvCreateImage( size, d, nChan);
sigma2_sq = cvCreateImage( size, d, nChan);
sigma12 = cvCreateImage( size, d, nChan);

temp1 = cvCreateImage( size, d, nChan);
temp2 = cvCreateImage( size, d, nChan);
temp3 = cvCreateImage( size, d, nChan);

ssim_map = cvCreateImage( size, d, nChan);
/*************************** END INITS **********************************/
// PRELIMINARY COMPUTING
cvSmooth( img1, mu1, CV_GAUSSIAN, 11, 11, 1.5 );
cvSmooth( img2, mu2, CV_GAUSSIAN, 11, 11, 1.5 );

cvPow( mu1, mu1_sq, 2 );
cvPow( mu2, mu2_sq, 2 );
cvMul( mu1, mu2, mu1_mu2, 1 );


cvSmooth( img1_sq, sigma1_sq, CV_GAUSSIAN, 11, 11, 1.5 );
cvAddWeighted( sigma1_sq, 1, mu1_sq, -1, 0, sigma1_sq );

cvSmooth( img2_sq, sigma2_sq, CV_GAUSSIAN, 11, 11, 1.5 );
cvAddWeighted( sigma2_sq, 1, mu2_sq, -1, 0, sigma2_sq );

cvSmooth( img1_img2, sigma12, CV_GAUSSIAN, 11, 11, 1.5 );
cvAddWeighted( sigma12, 1, mu1_mu2, -1, 0, sigma12 );


//////////////////////////////////////////////////////////////////////////
// FORMULA

// (2*mu1_mu2 + C1)
cvScale( mu1_mu2, temp1, 2 );
cvAddS( temp1, cvScalarAll(C1), temp1 );

// (2*sigma12 + C2)
cvScale( sigma12, temp2, 2 );
cvAddS( temp2, cvScalarAll(C2), temp2 );

// ((2*mu1_mu2 + C1).*(2*sigma12 + C2))
cvMul( temp1, temp2, temp3, 1 );

// (mu1_sq + mu2_sq + C1)
cvAdd( mu1_sq, mu2_sq, temp1 );
cvAddS( temp1, cvScalarAll(C1), temp1 );

// (sigma1_sq + sigma2_sq + C2)
cvAdd( sigma1_sq, sigma2_sq, temp2 );
cvAddS( temp2, cvScalarAll(C2), temp2 );

// ((mu1_sq + mu2_sq + C1).*(sigma1_sq + sigma2_sq + C2))
cvMul( temp1, temp2, temp1, 1 );

// ((2*mu1_mu2 + C1).*(2*sigma12 + C2))./((mu1_sq + mu2_sq + C1).*(sigma1_sq + sigma2_sq + C2))
cvDiv( temp3, temp1, ssim_map, 1 );


CvScalar index_scalar = cvAvg( ssim_map );

std::cout << "(R, G & B SSIM index)" << std::endl ;
std::cout << index_scalar.val[2] * 100 << "%" << std::endl ;
std::cout << index_scalar.val[1] * 100 << "%" << std::endl ;
std::cout << index_scalar.val[0] * 100 << "%" << std::endl ;

return 0;
}

最佳答案

实际上,cvConvert(img1_temp, img1); 在我的电脑上运行良好,img1 不是 NULL。但是我发现关于cvPow( mu1, mu1_sq, 2 );的另一个问题,因为在它之前,从未创建过mu1_sq,导致错误“cv::Exception at memory location ”。

我建议您使用较新的 C++ 语法编写 OpenCV 代码。

关于C++/openCV : cvConvert returns null,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21000558/

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