c++ - 如何处理 ListCtrl 标题中的右键单击事件？

Question

我正在寻找一种方法来确定右键单击列表 ctrl 的标题以显示上下文菜单。我有一个代码示例，但它不起作用。

void ExDialog::OnContextMenu(CWnd* pWnd, CPoint point)
{
    CListCtrl* pLC = (CListCtrl*) GetDlgItem(IDC_EXAMPLE);
    CHeaderCtrl* pHC = pLC->GetHeaderCtrl();
    if (pWnd->GetSafeHwnd()==pHC->GetSafeHwnd())
    {
        CMenu menu;
        VERIFY(menu.LoadMenu(IDR_HEADERMENU));
        CMenu* pPopup = menu.GetSubMenu(0);
        ASSERT(pPopup != NULL);
        CWnd* pWndPopupOwner = pHC;
        pPopup->TrackPopupMenu(TPM_LEFTALIGN | TPM_RIGHTBUTTON, point.x, point.y, pWndPopupOwner);
    }
}

Answer 1

你在那里得到 ListView 控件作为参数，然后你需要自己从那里找到标题:点击测试和/或比较坐标:

CListCtrl* pLC = (CListCtrl*) GetDlgItem(IDC_LIST1);
CHeaderCtrl* pHC = pLC->GetHeaderCtrl();
if (pWnd->GetSafeHwnd() == pLC->GetSafeHwnd()) // <<--- Not pHC!
{
    UINT nFlags = 0;
    pLC->HitTest(point, &nFlags);
    if(nFlags & LVHT_NOWHERE) // <<--- Header hits "nowhere"
    {
        CRect Position;
        pHC->GetWindowRect(Position);
        if(Position.PtInRect(point)) // <<--- point check 
        {
            CMenu menu;
            VERIFY(menu.LoadMenu(IDR_HEADERMENU));
            CMenu* pPopup = menu.GetSubMenu(0);
            ASSERT(pPopup != NULL);
            CWnd* pWndPopupOwner = pHC;
            pPopup->TrackPopupMenu(TPM_LEFTALIGN | TPM_RIGHTBUTTON, point.x, point.y, pWndPopupOwner);
        }
    }
}