c++ - ']' 标记之前的预期主表达式”

Question

//Purpose: To simulate the probability that a car will make a decision in a video game.
//40% of the time the car will turn left, 30% right, 20% straight, and 10% explode.

#include <iostream>
#include <cstdlib>
#include <time.h>
#include <iomanip>

using namespace std;

void GetCount( count[] );

int main()
{
  int count[4] = {0};
  unsigned int k;
  float theoretical;

  srand( (unsigned) time(NULL) );

  GetCount( int count[] );

  cout.setf( ios::showpoint | ios::fixed );
  cout << setprecision(2);
  cout << "                                 Car Simulation" << endl << endl
       << "                Number of        Experimental        Theoretical    % Error  " << endl
       << "             Times Selected        Percent             Percent               " << endl
       << "            ----------------    --------------      -------------    ------  " << endl;

  for ( k = 0; k < 4; k++ )
  {
      switch(k)
      {
          case 0:
              cout << "Left:     ";
              theoretical = 40;
              break;
          case 1:
              cout << "Right:    ";
              theoretical = 30;
              break;
          case 2:
              cout << "Straight: ";
              theoretical = 20;
              break;
          default:
              cout << "Explosion:";
              theoretical = 10;
              break;
      } // end switch 

           cout << setw( 12 ) << count[ k ] 
                << setw( 20 ) << count[ k ] / 10000.0 * 100.0
                << setw( 19 ) << theoretical 
                << setw( 13 ) << ( ( count[ k ] - theoretical * 100 ) / (theoretical * 100) * 100 )
              << endl << endl;
  } //end for 

cout << endl << endl;

system("PAUSE");
return 0;

} //end main

void GetCount( int count[] )
{
    int randNum;
    unsigned int k;

   for( k = 0; k < 10000; k++ )//generates random number 1-100 10,000 times
   {
      randNum = rand() % 100 + 1;

      if( randNum <= 100 && randNum > 60 )
           count[0]++; 
      else if( randNum <= 60 && randNum > 30 )
           count[1]++; 
      else if( randNum <= 30 && randNum > 10 )
           count[2]++; 
      else 
           count[3]++; 
  }//end for

}//end function definition

上面的代码是用来模拟汽车在视频游戏中做出决定的。

在十字路口，汽车有 40% 的时间会左转，30% 的时间会右转，20% 的时间会直行，还有 10% 的时间会爆炸。

程序执行 10,000 个这样的决定并输出结果。

除了函数“GetCount()”外，一切都很好。调用此函数时，应该会生成代表决策的随机数，并将每个数字生成的次数存储在它们的数组中。

但是，当我编译程序时，出现错误提示:

"in line 21, expected primary-expression before ']' token".

这是我调用函数的同一行。我已经尝试了一些方法来尝试修复它，但我不断收到一些错误。

如有任何建议，我们将不胜感激，谢谢。

Answer 1

GetCount( int count[] );

应该是

GetCount(count);

类型不必重复；编译器知道 count 与您刚刚声明为 int[] 的变量相同。