c++ - 是否有可能写入传递给函数的输入缓冲区超出预期？ (没有堆栈溢出)

Question

我正在做一些数据包翻译补丁。我的 dll 注入(inject)中文游戏， Hook recv，监听数据包并翻译收到的中文字符串。我一直在编码、编码和编码……直到我发现我应该如何在 buf 中写入超过数据包长度的内容？

int __stdcall Hooked_recv(SOCKET s, char *buf, int len, int flags)
{
    h_recv.PreHook();

    int ret_val = recv(s, buf, len, flags);
//ret_val is the number of bytes received. Ok, I can increase it, but...
//what to do with buf? Sure I can write there as much as no access violation appears.
//but I need a safe way.
//I guess if I do buf = new char[NEW_SIZE] then caller will fail to read buf because of pointer changed?
//what could I do to make received packet longer?
//I no want to reverse exe and increase buffer in hex editor. at least for now.

    h_recv.PostHook();

    return ret_val;
}

Answer 1

尽可能多地填充缓冲区。如果您有任何剩余，请将其保存以供下次调用您的 Hook 接收函数(将其放在首位，如果已填满，请重复保存新的剩余)。您将需要使用缓冲区，这是不可避免的。