javascript - 如何通过javascript改变ng-click状态？

Question

我需要让代码在条件为真时运行

if document.getElementByClass('toggle').style.visibility == 'visible'

应该就像在我的页面中写的那样

ng-click="toggle = !toggle"

但是如何在我的 javascript 文件中选择切换状态？

编辑:更多信息

div(ng-controller='ViewsCtrl', ng-class="toggle ? 'nav-open' : 'nav'")
  .container
    .logo
      img(src='images/logo.png')
      span Motto

    ul(ng-class="toggle ? 'menu-open' : 'menu'")
      li
        a(ng-click="changeView('home')") Home
      li
        a(ng-click="changeView('products')") Products

    button.toggle(ng-click='toggle = !toggle') Menu

Controller

appControllers.controller 'ViewsCtrl', [
  '$scope'
  '$location'

  Ctrl = ($scope, $location) ->

    $scope.changeView = (view) ->
      $location.path view
      if document.getElementByClass('toggle').style.visibility == 'visible'
        $scope.toggle = !toggle
      return

    return

]

Answer 1

看这个:

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div ng-app>
  <input type="button" ng-click="toggle = !toggle" value="{{toggle?' Hide':' Show'}}"/>
  <div ng-show="toggle">shown</div>
</div>