swift - 为什么 swift 不会重新计算 'if' 语句？

Question

我正在尝试创建一个非常简单的“猜谜游戏”，用户必须猜测计算机有多少根手指(最多 5 根手指)。

事情是这样的。当代码执行并且我按下提交时，即使打印日志注册了正确的数字，应用程序仍会打印 if 语句以表示不正确。我哪里错了？

import UIKit

类 ViewController: UIViewController {

override func viewDidLoad() {
    super.viewDidLoad()
    // Do any additional setup after loading the view, typically from a nib.
}

override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
    // Dispose of any resources that can be recreated.
}




@IBOutlet weak var fingerInput: UITextField!

@IBOutlet weak var fingerResult: UILabel!

@IBAction func fingerSubmit(sender: AnyObject) {

    let realNumberofFingers = Int(arc4random_uniform(6))

    print(realNumberofFingers)

    if fingerInput != realNumberofFingers {

        fingerResult.text = "Gosh darn, that's wrong!"

    } else if fingerInput == realNumberofFingers {

        fingerResult.text = "Thats right!"

    }
}

Answer 1

您正在比较 actual UITextField fingerInput 与 realNumberofFingers。这是错误的，并且总是会产生 false。您应该做的是解析 fingerInput 中的字符串并检查该字符串中包含的整数是否等于 realNumberofFingers:

@IBAction func fingerSubmit(sender: AnyObject) {

    let input = Int(fingerInput.text!)

    if let enteredFingers = input {
        let realNumberofFingers = Int(arc4random_uniform(6))
        print(realNumberofFingers)

        if enteredFingers == realNumberofFingers {
            fingerResult.text = "Thats right!"
        } else {
            fingerResult.text = "Gosh darn, that's wrong!"
        }
    } else {
        fingerResult.text = "Please enter a correct guess - an integer!"
    }
}