swift - 将按钮放在 tableview 单元格上时崩溃，无法识别的选择器

Question

PatientTableViewCell viewBtn:]: unrecognized selector sent to instance 0x7fdde280ac00

libc++abi.dylib: terminating with uncaught exception of type NSException

有什么想法吗？谢谢

   func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell
{
    let current_patient = patients[indexPath.row]
    let cell = myTable.dequeueReusableCellWithIdentifier("patientCell", forIndexPath: indexPath) as! PatientTableViewCell
    let type = current_patient.enrollable_type
    var unique_id = current_patient.unique_id
    cell.patientTypelbl.text = type
    cell.patientIDlbl.text = unique_id
    cell.viewBtn.tag = indexPath.row
    cell.viewBtn.addTarget(self, action: "viewDetailAction:", forControlEvents: .TouchUpInside)
    return cell
}

   @IBAction func viewDetailAction(sender: UIButton){
    print("clicked")
    self.performSegueWithIdentifier("patientDetailCell", sender: self)
}

对于 patientTableviewcell:

 class PatientTableViewCell: UITableViewCell {

@IBOutlet weak var viewBtn: UIButton!
@IBOutlet weak var titleType: UILabel!
@IBOutlet weak var titleID: UILabel!
@IBOutlet weak var patientTypelbl: UILabel!
@IBOutlet weak var patientIDlbl: UILabel!
override func awakeFromNib() {
    super.awakeFromNib()
    // Initialization code
}

override func setSelected(selected: Bool, animated: Bool) {
    super.setSelected(selected, animated: animated)

    // Configure the view for the selected state
}

Answer 1

您的错误是在 xCode 编辑器中设置了一个 IBAction，然后以编程方式将选择器目标添加到同一按钮。

首先从 Referencing Outlets 中删除您的 IBAction 设置，如图中所示:

之后，您必须通过删除 IBAction 标记来重命名您的函数:

func viewDetailAction() {...}