c++ - node, & node 和 node->next in 链表的区别

Question

// Program to insert node at front in linked list.

//这是一个简单的链表程序，但我不明白两者之间的区别 //&newNode、newNode 和 newNode 的值->next

void PushAtFrontLinkList(int value)
{
    if(head==NULL)
    {

        head=tail;
    }
    node* newNode=new node();
    newNode->data=value;
    newNode->next=head; 
    head=newNode;


    // Trying to differentiate between data contained in newNode and &newNode and newNode->next
    cout<<"just new node"<<newNode<<endl; // what will be contained in newNode?     cout<<"address of node"<<&newNode<<endl; // what will be contained in &newNode?  
    cout<<"new node next"<<newNode->next<<endl; // It will be the address of the next node?


}

Answer 1

newNode 将包含您刚刚创建的新节点对象的地址。对于 newNode->next，它包含列表中下一个节点的地址。

注意最后，newNode 将成为链表的头部，newNode->next 将指向旧的头部。