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此程序是玩家与计算机之间的简单井字游戏。如果所述空间尚未被占用,则计算机只会生成一个随机空间以移动到该空间。此外,我在垂直轴上设置了 x 坐标,而在水平轴上设置了 y 坐标。我这样做是因为我使用了二维数组,这就是它们的结构。
程序运行时,部分空格出现错误,无法查明原因。当用户输入点 (0,2) 时,程序也会填充点 (1,0),反之亦然。这也发生在点 (1,2) 和 (2,0) 上。
#include<iostream>
#include<string>
#include<stdlib.h>
#include<ctime>
using namespace std;
int board[2][2];
int chooseFirstPlayer();
void userMove(int boardArray[2][2]);
void compMove(int boardArray[2][2]);
int checkIfWinner(int boardArray[2][2]);
void displayBoard(int boardArray[2][2]);
int main(){
srand(time(NULL));
int x,y,winner;
for(x = 0; x <= 2; x++){ //sets the enitre board array to 0
for(y = 0; y <= 2; y++){
board[x][y] = 0;
}
}
if (chooseFirstPlayer() == 1){ //the user gets to movve first
do{//it will loop this until there is a winner
displayBoard(board);
userMove(board);
displayBoard(board);
winner = checkIfWinner(board);
if (winner == 0){//after the player moves, it will see if he won. If not, then the computer willbe able to move.
compMove(board);
displayBoard(board);
winner = checkIfWinner(board);
}
}while (winner == 0);//it will loop until a winner is found
}
else{//same structure as above just slightly altered to allow the computer to move first
do{
compMove(board);
displayBoard(board);
winner = checkIfWinner(board);
if (winner == 0){
userMove(board);
displayBoard(board);
winner = checkIfWinner(board);
}
}while(winner == 0);
}
if (winner = 1){
cout << "Congratulations, you won!";
}
else if (winner = 2){
cout << "Sorry, you lost!";
}
}
int chooseFirstPlayer(){//randomly genereate a number 1 or 2 to choose who moves first
return rand() % 2 + 1;
}
void userMove(int boardArray[2][2]){
int userX, userY;
do{
cout << "Enter an x coordinate: "<<endl;
cin >> userX;
cout << "Enter a y coordinate: "<<endl;
cin >> userY;
if (boardArray[userX][userY] != 0){
cout << "That loaction is already occupied"<<endl;
}
}while(boardArray[userX][userX] != 0);
boardArray[userX][userY] = 1;
}
void compMove(int boardArray[2][2]){
int compX,compY;
do{
compX = rand() % 3;
compY = rand() % 3;
}while(boardArray[compX][compY] != 0);
boardArray[compX][compY] = 2;
}
int checkIfWinner(int boardArray[2][2]){
if(boardArray[0][0] == boardArray[0][1] && boardArray[0][1] == boardArray[0][2]){ //across
return boardArray[0][0];}
else if (boardArray[1][0] == boardArray[1][1] && boardArray[1][1] == boardArray[1][2]){
return boardArray[1][0];}
else if (boardArray[2][0] == boardArray[2][1] && boardArray[2][1] == boardArray[2][2]){
return boardArray[2][0];}
else if (boardArray[0][0] == boardArray[1][0] && boardArray[1][0] == boardArray[2][0]){//down
return boardArray[0][0];}
else if (boardArray[0][1] == boardArray[1][1] && boardArray[1][1] == boardArray[2][1]){
return boardArray[0][1];}
else if (boardArray[0][2] == boardArray[1][2] && boardArray[1][2] == boardArray[2][2]){
return boardArray[0][2];}
else if (boardArray[0][0] == boardArray[1][1] && boardArray[1][1] == boardArray[2][2]){//diagonal
return boardArray[0][0];}
else if (boardArray[2][0] == boardArray[1][1] && boardArray[1][1] == boardArray[0][2]){
return boardArray[2][0];}
else{
return 0;
}
}
void displayBoard(int boardArray[2][2]){
system("CLS");
cout <<" "<<" Y1 "<<" Y2 "<<" Y3 "<<endl;
cout <<" X1 "<< "__"<<boardArray[0][0]<<"__|__"<<boardArray[0][1]<<"__|__"<<boardArray[0][2]<<"__"<<endl;
cout <<" X2 "<< "__"<<boardArray[1][0]<<"__|__"<<boardArray[1][1]<<"__|__"<<boardArray[1][2]<<"__"<<endl;
cout <<" X3 "<< " "<<boardArray[2][0]<<" | "<<boardArray[2][1]<<" | "<<boardArray[2][2]<<" "<<endl;
}
我的IDE是Dev-C++ (5.4.2)
最佳答案
你的数组是 2x2,你这样做:
for(x = 0; x <= 2; x++){ //sets the enitre board array to 0
for(y = 0; y <= 2; y++){
board[x][y] = 0;
}
}
然后你访问了你不应该访问的内存。这意味着你要出界了!
这里 x
和 y
最终将取一个等于 2 的值。
数组的索引从 0 开始,直到它的大小为 - 1。
因此,您可以使用 3x3 数组,或更改您的代码(以及直到 2 的函数 checkIfWinner
)。
旁注:
你在这里错过了相等运算符:
if (winner = 1){
cout << "Congratulations, you won!";
}
else if (winner = 2){
cout << "Sorry, you lost!";
}
如果你保持原样,会发生什么?分配将发生并导致逻辑真,因此第一个条件将始终为真(第二个条件将始终为真,但代码不会走那么远)。
因此,将 =
更改为 ==
。
关于c++ - 井字棋数组错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26741530/
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