javascript - 复杂对象数据结构转xlsx

Question

我有一个 javascript 对象，它本身包含其他对象:

{
    "10": {},
    "12": {
        "20": {
            "value": 1,
            "id": 1,
        },
        "100": {
            "value": 12,
            "id": 1,
        }
    },
    "14": {
        "100": {
            "value": 14,
            "id": 2,
        }
    },
    "16": {},
    "18": {},
    "20": {
        "100": {
            "value": 23,
            "id": 1,
        },
        "150": {
            "value": 56,
            "id": 3,
        }
    },
    "22": {},
    "24": {},
    "26": {
        "50": {
...

我想将其导出为 xlsx 文件，但这样做时遇到一些问题。

我主要使用 js-xlsx这对于它的文档来说不是很有帮助，并且 alasql .

为更简单的数据结构创建这样的文件非常容易。但是当我尝试用自己的结构创建它时遇到了一些问题。

首先尝试这样做:

alasql('SELECT * INTO XLSX("test.xlsx",{headers:true}) FROM ?',[$scope.TestData]);

无法打印[Object]而不是实际值。

尝试自己创建单元格，但最终得到一个空文件。

function sheet_from_array_of_arrays(data, opts) {
    var ws = {};
    var range = {s: {c:10000000, r:10000000}, e: {c:0, r:0 }};
    var row1 = 0;
    for (var R in data) {
        if (data.hasOwnProperty(R)) {
            var row2 = 0;
            for (var C in data[R]) {
                if (data[R].hasOwnProperty(C)) {
                var col = 0;
                    for (var K in data[R][C]) {
                        if (data[R][C].hasOwnProperty(C)) {
                            var RR = row1 + row2;
                            var CC = col;
                            if(range.s.r > RR) range.s.r = RR;
                            if(range.s.c > CC) range.s.c = C;
                            if(range.e.r < RR) range.e.r = RR;
                            if(range.e.c < CC) range.e.c = CC;
                            var cell = {v: data[R][C][K] };
                            if(cell.v == null) continue;
                            var cell_ref = XLSX.utils.encode_cell({c:CC,r:RR});

                            if(typeof cell.v === 'number') cell.t = 'n';
                            else if(typeof cell.v === 'boolean') cell.t = 'b';
                            else if(cell.v instanceof Date) {
                                cell.t = 'n'; cell.z = XLSX.SSF._table[14];
                                cell.v = datenum(cell.v);
                            }
                            else cell.t = 's';

                            ws[cell_ref] = cell;

                            col = col + 1;
                        }
                    }
                    row2 = row2 + 1;
                }
            }
            row1 = row1 + 1;
        }
    }
    if(range.s.c < 10000000) ws['!ref'] = XLSX.utils.encode_range(range);
    return ws;
}

function Workbook() {
    if(!(this instanceof Workbook)) return new Workbook();
    this.SheetNames = [];
    this.Sheets = {};
}

var wb = new Workbook(), ws = sheet_from_array_of_arrays($scope.TestData);

/* add worksheet to workbook */
wb.SheetNames.push(ws_name);
wb.Sheets[ws_name] = ws;
var wbout = XLSX.write(wb, {bookType:'xlsx', bookSST:true, type: 'binary'});

function s2ab(s) {
    var buf = new ArrayBuffer(s.length);
    var view = new Uint8Array(buf);
    for (var i=0; i!=s.length; ++i) view[i] = s.charCodeAt(i) & 0xFF;
    return buf;
}
saveAs(new Blob([s2ab(wbout)],{type:"application/octet-stream"}), "test.xlsx")

有没有办法让我使用上面提供的对象创建 xlsx 文件？

Answer 1

您可以使用SEARCH用于解析嵌套 JSON 对象的运算符:

var data = {
"10": {},
"12": {
    "20": {
        "value": 1,
        "id": 1,
    },
    "100": {
        "value": 12,
        "id": 1,
    }
},
"14": {
    "100": {
        "value": 14,
        "id": 2,
    }
},
"16": {},
"18": {},
"20": {
    "100": {
        "value": 23,
        "id": 1,
    },
    "150": {
        "value": 56,
        "id": 3,
    }
}
};


  var res = alasql('SEARCH OF(@a) OF(@c) \
    RETURN(@a AS a,@c AS c, _->[value] AS [value], _->id AS id) \
    INTO XLSX("test406.xlsx",{headers:true}) \
    FROM ?',[data]);

这里:

• 搜索...到 XLSX 中？ - 特殊搜索运算符
• OF(@v) - 对象的键列表(键值将存储到变量中
• RETURN(...) - 结果对象
• _ - 当前搜索值