c++ - 为 C++ 编写不递增的味觉测试程序

Question

我正在为一个类编写一个口味测试程序，它会在我的 if 语句之前运行良好。但是，一旦我进入我的 if 语句，它就不会递增 i，所以它永远不会离开 while 循环。

   #include <iostream>
using namespace std;

void main()
{
    int i = 0;
    int q = 0;
    int p = 0;
    int c = 0;
    char preference;
    int x = 0;
    cout << "How many taste tests would you like to do?" << endl;
    cin >> x;
    while (i<x)
    {
        cout << "Do you prefer Coke, Pepsi, or are they the same? Use c for coke, p for pepsi, and q for the same\n";
        cin >> preference;
        if (preference == 'q' || preference == 'Q')
        {
            q = q + 1;
            i++;
        }
        if (preference == 'p' || preference == 'P')
        {
            p = p + 1;
            i++;
        }
        if (preference == 'c' || preference == 'C')
        {
            c = c + 1;
            i++;
        }

    }
    if (p>q)
    {
        cout << "Pepsi wins" << endl;
        if (c>p)
            cout << "Coke wins" << endl;
        if (c == p)
            cout << "Tie" << endl;
    }
}

Answer 1

我认为您正在尝试检查确定的字符是否被 cin >> preference 单击，但您正在测试 int 变量，所以如果我按 'q '

//if(preference==q || preference==Q) // 'q'==0 || 'p'==0
if(preference=='q' || preference=='Q') // 'q'=='q' || 'q'=='Q'

所以添加''

希望对你有帮助