c++ - 乘以 2 个隐藏变量的类中的函数

Question

Create a class with two variables as data members and create a member function to multiply it?

 class Madina{
  int n1,n2 ;

 public:int getN1(){
   return n1 ;
 }
 public:int getN2(){
   return n2 ;
 }
 public:int setN1(int new_n1){
   n1 = new_n1 ;
 }
 public:int setN2(int new_n2){
   n2 = new_n2 ;
 }
public:int func(){
  return n1*n2;
}

};


int main(){

  Madina example ;
  int n1 =0;
  int n2 =0;
  cout << "Input"<<endl ;
  cout << "Enter 1st number"<<endl;
  cin >> n1 ;
  cout << "Enter 2nd number"<<endl ;
  cin >> n2 ;

  example.setN1(n1);
  example.setN2(n2);

  cout << "get n1 " << example.getN1()<<endl;
  cout << "get n2 " << example.getN2()<<endl;

  cout << "Output product is "<< example.func()<<endl ;
  return 0 ;


}

我不知道为什么程序会崩溃......没有任何解释!

Answer 1

我稍微修改了你的代码。

为什么您的 setter 方法返回整数？ Setter 方法不应该返回任何东西？我已经测试了这段代码，它对我来说工作正常。

同样如上所述，方法只需要公开一次而不是单独公开。

#include <iostream>

class Madina {
    int n1,n2 ;

    public:
    int getN1() {
        return n1 ;
    }
    int getN2() {
        return n2 ;
    }
    void setN1(int new_n1) {
        n1 = new_n1 ;
    }
    void setN2(int new_n2) {
        n2 = new_n2 ;
    }
    int func() {
        return n1*n2;
    }
};

using namespace std;
int main() {
    Madina example;
    int n1 =0;
    int n2 =0;
    cout << "Input"<<endl;
    cout << "Enter 1st number"<<endl;
    cin >> n1;
    cout << "Enter 2nd number"<<endl;
    cin >> n2;

    example.setN1(n1);
    example.setN2(n2);

    cout << "get n1 " << example.getN1()<<endl;
    cout << "get n2 " << example.getN2()<<endl;

    cout << "Output product is "<< example.func()<<endl ;
    return 0 ;
}

此外，应该有 C++ 标签而不是其他用户提到的 Java 标签。