php - 无法遍历此字典并组织成自定义结构

Question

我有这段代码用于迭代数组 playerForm。

playerForm 数组中包含每个玩家的数组，并包含每个玩家的表单。

即

["playerForm": {
1 =     (
            {
        date = "2017-01-31";
        name = Dicky;
        result = L;
        "results_id" = 42;
    },
            {
        date = "2017-01-26";
        name = Dicky;
        result = L;
        "results_id" = 41;
    }
  );
2 =     (
            {
        date = "2017-01-25";
        name = G;
        result = W;
        "results_id" = 38;
    },
            {
        date = "2017-01-25";
        name = G;
        result = D;
        "results_id" = 40;
    }
3 =     (
            {
        date = "2017-01-31";
        name = Sultan;
        result = W;
        "results_id" = 42;
    },
            {
        date = "2017-01-26";
        name = Sultan;
        result = W;
        "results_id" = 41;
    }
    );
    }]

这是我尝试使用的代码:

  let json = try JSONSerialization.jsonObject(with: data!, options: .allowFragments) as? [String:AnyObject]
                    print (json!)

                    if let dict = json?["playerForm"] as? [String:Any] {

                        print ("step 1")

                        for value in dict {
                            if let arr = value as? [[String:Any]] {
                                print(arr)
                                self.leagueForm = arr.flatMap { Form($0) }

                                for form in self.leagueForm {
                                    self.formGuide.append(form.player_result!)
                                }
                                print ("break")

                            }
                        }


                        print (self.formGuide)
                    }

这是我用来组织数据的自定义结构；

 struct Form {
    var player_result: String?
    var player_name: String?
    var result_date: String?
    var result_id: String?

    init(_ dictionary: [String : Any]) {
        self.player_result = dictionary["result"] as? String ?? ""
        self.player_name = dictionary["name"]  as? String ?? ""
        result_date = dictionary["date"]  as? String ?? ""
        result_id = String(dictionary["results_id"]  as? Int ?? 0)


    }
}

var leagueForm = [Form]()

但是，我收到警告:Cast from '(key: String, value: AnyObject)' to unrelated type [[String : Any]] always fails。

这是我提供初始数组的 PHP 脚本:

$noPlayers = count($communityPlayersIds); //
$playerForm = array();
$playerForm = $dao->getCommunityForm($communityId, $noPlayers, $communityPlayersIds);

public function getCommunityForm($communityId, $noPlayers, $communityPlayersIds){
$sql = " SELECT IF(player1_id=?, player1_result, player2_result) AS result, IF(player1_id=?, player1_name, player2_name) AS name, date, results_id FROM `results` WHERE (player1_id=? OR player2_id=?) AND community_id=? ORDER BY date DESC Limit 8";
$stmt = $this->conn->prepare($sql);
$i = 0;
foreach ($communityPlayersIds as $cPI) {
    $i++;
    $stmt->bind_param("iiiii", $cPI, $cPI, $cPI, $cPI, $communityId);
    $stmt->execute();
    if ($result = $stmt->get_result()) {
        while($row = $result->fetch_array(MYSQLI_ASSOC)){
             $returnValue[$i][] = $row;
             }
        }
    }return $returnValue;
}

echo json_encode (array('playerForm' => $playerForm ));

所以上面例子中的这个 1,2,3 是我如何索引从 MySQL 返回的结果。我这样做是为了分离数据，以便我可以在 Swift 中构造它

我哪里错了？

Answer 1

我认为你的问题出在这行代码上

if let arr = value as? [[String:Any]] {

查看您的 JSON 文件，我可以看到您的 json 对象是这种格式:

["playerForm": {
1 =     (
            {
        date = "2017-01-31";
        name = Dicky;
        result = L;
        "results_id" = 42;
    },
            {
        date = "2017-01-26";
        name = Dicky;
        result = L;
        "results_id" = 41;
    }
  );...

所以你的 json 根对象是一个 [String : Any] 字典，你做对了。字典只有一对(键，值)，键为“PlayerForm”。之后你假设那对的值是 [[String:Any]] 类型的，这将是一个字典数组的数组，我不认为它是:)我认为这部分:

2 =     (
            {

在 JSON 文件中有点错误，我不太确定“2=”应该代表什么，但它不是数组，因为数组不包含键，如“1,2, 3……”。

我建议将值转换为其他值，也许可以尝试

某物 = 值(value)为？ [字符串:任何]

如果可行，那么您可以将该字典中的值转换为 NSArray 以进行迭代。

只是和那里的 Actor 一起玩了一会儿:)