ios - UIBezierPath 只有半个笔画

Question

当我尝试使用以下代码绘制如下形状时，该形状仅显示半笔划线。

let shape = SKShapeNode()
            shape.path = createPointerPath().cgPath
            shape.position = CGPoint(x: frame.midX, y: frame.midY)
            shape.fillColor = UIColor(red: 1.0, green: 0.439, blue: 0.678, alpha: 1.0)
            shape.strokeColor = .white
            shape.lineWidth = 2
            addChild(shape)

创建形状:

func createPointerPath() -> UIBezierPath {

    let pointerPath = UIBezierPath()
    pointerPath.move(to: CGPoint(x:0, y:0))

    pointerPath.addCurve(to: CGPoint(x:0, y:100), controlPoint1: CGPoint(x:-10, y:0), controlPoint2: CGPoint(x:-50, y:100))
    pointerPath.addCurve(to: CGPoint(x:0, y:0), controlPoint1: CGPoint(x:50, y:100), controlPoint2: CGPoint(x:10, y:0))

    pointerPath.stroke()        
    pointerPath.close()
    return pointerPath
}

如果我将 x 设置为 10，它会显示另一条 half stroe 线，但形状没有闭合。

    pointerPath.addCurve(to: CGPoint(x:10, y:0), controlPoint1: CGPoint(x:50, y:100), controlPoint2: CGPoint(x:10, y:0))

有什么建议吗？谢谢!

Answer 1

这是我尝试后得到的；希望对你有帮助

    let v : UIView = UIView.init(frame: CGRect.init(x: 50, y: 50, width: 200, height: 200))
    v.layer.borderWidth = 2.0
    let shape = CAShapeLayer()
    shape.path = createPointerPath().cgPath
    shape.position = CGPoint(x: frame.midX, y: frame.midY)
    shape.fillColor = UIColor(red: 1.0, green: 0.439, blue: 0.678, alpha: 1.0).cgColor
    shape.strokeColor = UIColor.white.cgColor
    shape.lineWidth = 2
    v.layer.addSublayer(shape)
    self.addSubview(v)

这与您提供的功能相同:

func createPointerPath() -> UIBezierPath {

    let pointerPath = UIBezierPath()
    pointerPath.move(to: CGPoint(x:0, y:0))

    pointerPath.addCurve(to: CGPoint(x:0, y:100), controlPoint1: CGPoint(x:-10, y:0), controlPoint2: CGPoint(x:-50, y:100))
    pointerPath.addCurve(to: CGPoint(x:0, y:0), controlPoint1: CGPoint(x:50, y:100), controlPoint2: CGPoint(x:10, y:0))

    pointerPath.stroke()
    pointerPath.close()
    return pointerPath
}

输出: