c++ - Setenv:在初始值设定项中将类型表达式列表视为复合表达式

Question

获取 在初始化程序中将类型表达式列表视为复合表达式在这两个函数调用上 -

    char itoa(new_total, new_total_ch, 10);
    int setenv("COUNT_TOTAL", new_total_ch, 1);

这是代码片段-

#include <iostream>
// create process team
#include <stdio.h>
#include <unistd.h>
#include <stdlib.h>
#include <sys/types.h>
#include <sys/wait.h>
#include <ctime>
// initialize & process
#include <time.h>
#include <string>
#include <fstream>
#include <cmath>
#include <iosfwd>
// initialize & process
using std::ifstream;
using namespace std;

class Count3sProcessParallel {

public:
    //int process();
    int pr_count;
    int process();
    typedef int COUNT_TOTAL;


private:

    int worker;
    //declare process()
    long unit_of_work;
    long lower_bound;
    long upper_bound;
    int pr_i;
    char * ct;
    int ct_i;
    int new_total;
    char itoa();
    char * new_total_ch;
    int setenv();

};


int Count3sProcessParallel::process() {
    // determine upper lower bounds
    unit_of_work = in_length/workers_num;
    lower_bound = (worker -1) * unit_of_work;
    upper_bound = (worker * unit_of_work) -1;

    // iterate and count
    pr_count = 0;
    for (pr_i = lower_bound; pr_i < upper_bound; pr_i++)
      if (floor(in_buffer[pr_i] == 3))
        pr_count++;
        return pr_count;

    //update COUNT_TOTAL
    ct = getenv("COUNT_TOTAL");
    ct_i = atoi(ct);
    new_total = (pr_count + ct_i);
    char * new_total_ch[33];
    char itoa(new_total, new_total_ch, 10);
    int setenv("COUNT_TOTAL", new_total_ch, 1);

    delete[] in_buffer;
    return 0;
}

我该如何解决这个问题？谢谢。

Answer 1

删除前导类型。只需使用:

itoa(new_total, new_total_ch, 10);
setenv("COUNT_TOTAL", new_total_ch, 1);