C++ 重载 += 带有双指针的运算符

Question

所以我试图为字典程序赋值重载 += 运算符。这是我的功能:

Definition& Definition::operator += (const String& input) {
    String** temp;
    temp = new String*[numDefs + 1];
    temp[0] = new String[numDefs];
    for (int i = 0; i < numDefs; i++)   {
            temp[i] = def[i];
    }
    temp[0][numDefs] = input;
    delete[] def;
    def = temp;
    numDefs++;
    return *this;
}

但是，当我尝试将“输入”放入“临时”时，它似乎不起作用。这是我的 String 类函数，用于将字符串分配给字符串:

String& String::operator=(const String& input) {
    data = NULL;
    (*this) = input.getData();
    return *this;
}

和:

String& String::operator=(const char* input) {
    if (data != input)
    {
        if (data != NULL)
        {
            delete[] data;
            data = NULL;
        }
        data_len = strSize(input);
        if (input != NULL)
        {
            data = new char[data_len + 1];
            strCopy(data, input);
        }
    }
    return *this;
}

似乎找不到问题。

Answer 1

一分钟前有个回答被用户删了帮我，我把代码改成:

Definition& Definition::operator += (const String& input) {
    String** temp;
    int tempSize = numDefs + 1;
    temp = new String*[tempSize];
    for (int i = 0; i < numDefs; i++)   {
        temp[i] = new String;
        temp[i] = def[i];
    }
    temp[numDefs] = new String;
    (*temp[numDefs]) = input;
    delete[] def;
    def = temp;
    numDefs = tempSize;
    return *this;
}

不管是谁，谢谢!