javascript - 类型错误 : fun is not a function

Question

当我调用OpenModelWindow函数时显示错误fun不是函数这是我的函数代码

function OpenModelWindow(url, option) {

        var fun;
        try {
            if (parent != null && parent.$ != null && parent.$.ShowIfrmDailog != undefined) {
                fun = parent.$.ShowIfrmDailog
            }
            else {
                fun = $.ShowIfrmDailog;
            }
        }
        catch (e) {
            fun = $.ShowIfrmDailog;
        }
        fun(url, option);
    }

Answer 1

那是因为有趣(如果可能未定义)。要解决这个问题，请检查 fun 的类型:

function OpenModelWindow(url, option) {

    var fun;
    try {
        if (parent != null && parent.$ != null && parent.$.ShowIfrmDailog != undefined) {
            fun = parent.$.ShowIfrmDailog
        }
        else {
            fun = $.ShowIfrmDailog;
        }
    }
    catch (e) {
        fun = $.ShowIfrmDailog;
    }
    if (typeof fun == 'function') // <----
        fun(url, option);
}