javascript - 如何修改此功能以获得最受欢迎的视频？ (YouTube API v3)

Question

我使用以下方法获取 YouTube 用户的视频列表。

首先，它查找用户 channel 的播放列表，然后查找该播放列表的视频标题。

It display the most recent videos. I need to get most popular videos. How to modify this function to get most popular videos?

// Get Uploads Playlist
$.get(
   "https://www.googleapis.com/youtube/v3/channels",{
   part : 'contentDetails', 
   forUsername : 'USER_CHANNEL_NAME',
   key: 'YOUR_API_KEY'},
   function(data) {
      $.each( data.items, function( i, item ) {
          pid = item.contentDetails.relatedPlaylists.uploads;
          getVids(pid);
      });
  }
);

//Get Videos
function getVids(pid){
    $.get(
        "https://www.googleapis.com/youtube/v3/playlistItems",{
        part : 'snippet', 
        maxResults : 20,
        playlistId : pid,
        key: 'YOUR_API_KEY'},
        function(data) {
            var results;
            $.each( data.items, function( i, item ) {
                results = '<li>'+ item.snippet.title +'</li>';
                $('#results').append(results);
            });
        }
<!--In your HTML -->
<ul id="results"></ul

Answer 1

您可以尝试使用videos.list方法并将图表参数的值设置为mostPopular。

chart - The chart parameter identifies the chart that you want to retrieve.

Acceptable values are:

• mostPopular – Return the most popular videos for the specified content region and video category.

https://www.googleapis.com/youtube/v3/videos?chart=mostPopular&key={YOUR_API_KEY}&part=snippet&maxResults=4

有关更多信息，请查看此 page .