c++ - 如何将枚举值分配给用户定义的 double 变量？？ C++

Question

您好，我是一名学生，所以我想说声抱歉，如果我写得很累，请随时指正。

我遇到以下问题 我正在尝试将一个枚举 int 值分配给另一个 double 变量以进行一次乘法运算。所以变量 costOfRoom 应该取属于枚举的值 D 或 T 或 S。 (D=200,T=150,S=110)

这必须由用户完成。

但找不到任何方法，我试图将第二个变量设为字符串类型，但它再次不起作用。它只会像字符串一样正常使用字符:(

还尝试了 cin >> type_Ofroom costofroom ;但我认为这是在 Java 中使用的？？

搜了论坛也没有类似的答案:(

程序运行良好，没有任何编译错误:)

谢谢你的时间

/* build a software system which will allow a hotel receptionist,
to enter in bookings for guests who come to the desk.
The system should display the room options as:
Room        Price       Code
---------------------------------------------------------------
Deluxe Room £200         D
Twin Room       £150     T
Single      £110         S

The receptionist should be prompted to enter in the room type and the number of 
nights a guest wishes to stay for and then calculate the amount
they need to pay. 
   */

// solution 
#include <iostream>
using namespace std;
int main() {

    // decleration of variables 
    double number_OfDays = 0, Totalcost = 0, costofroom = 0;
    enum   type_Ofroom { D = 200, T = 150, S = 150 };
    cout << "enter the type of the room " << endl << endl;

    //input of room type
    cin >> costofroom; // **here is the problem**  i am trying to give the 
                       //    values of the enum varaiable 
                        // it should have D or T or S but i cant  make it
    cout << "enter the number of the days " << endl << endl;

    //input of days
    cin >> number_OfDays;

    // calculation 
    Totalcost = costofroom * number_OfDays;

    // result 
    cout << "the costumer has to pay " << Totalcost << " pounds" << endl << endl;
    return 0;
}

Answer 1

您可以读入一个double，然后检查您的enum 值:

//input of room type
while (1)
{
    cin >> costofroom;
    if (costofroom == 0.0)
        costofroom = D;
    else if (costofroom == 1.0)
        costofroom = T;
    else if (costofroom == 2.0)
        costofroom = S;
    else
    {
        cout << "You didn't enter a valid option" << endl;
        continue;
    }
    break;
}

但是，最好读入一个int，然后再设置您的double。

double costofroom;
int option;

...

//input of room type
while (1)
{
    cin >> option;
    if (option == 0)
        costofroom = D;
    else if (option == 1)
        costofroom = T;
    else if (option == 2)
        costofroom = S;
    else
    {
        cout << "You didn't enter a valid option" << endl;
        continue;
    }
    break;
}