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c++ - 从派生类调用的复制构造函数

转载 作者:行者123 更新时间:2023-11-28 06:00:36 25 4
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有人可以解释这里的输出吗? createTreap()工作正常,r 不是 nullptr,而是 createTreapPair()叶子 r == nullptrtreapPair.first.display(); treapPair.second.display(); 之后.为什么?两者有什么区别?这是怎么回事?

#include <iostream>
#include <memory>

class BinaryTree {
public:
class Node {
int value;
std::shared_ptr<Node> left = nullptr, right = nullptr, parent = nullptr;
friend class BinaryTree; friend class Treap;
public:
Node (int v) : value(v) {}
virtual ~Node() = default;
Node (const Node&);
};
BinaryTree() : root(nullptr) {}
BinaryTree (const BinaryTree& other) : root(std::shared_ptr<Node>(new Node(*other.root))) {std::cout << "BinaryTree copy constructor called.\n";}
void setRoot (const std::shared_ptr<Node>& node) {root = node;}
protected:
std::shared_ptr<Node> root;
};

BinaryTree::Node::Node (const Node& other) : value(other.value) {
std::cout << "Node copy constructor called, value = " << value << '\n';
if (other.left) left = std::shared_ptr<Node>(new Node(*other.left));
if (other.right) right = std::shared_ptr<Node>(new Node(*other.right));
}

class Treap : public BinaryTree {
public:
class Node : public BinaryTree::Node {
int priority;
friend class Treap;
public:
Node (int value) : BinaryTree::Node(value), priority(std::rand() % 100) {}
Node (const Node& other) : BinaryTree::Node(other), priority(other.priority) {} // Treap::Node copy constructor.
};
void display() const {
std::shared_ptr<Node> r = std::dynamic_pointer_cast<Node>(root); // Casting from BinaryTree::Node to Treap::Node.
std::cout << "r = " << r << '\n';
if (root) std::cout << "Root exists and has value " << root->value << ".\n";
}
};

Treap createTreap() {
std::cout << "\n\ncreateTreap() called.\n";
Treap treap;
std::shared_ptr<Treap::Node> r = std::make_shared<Treap::Node>(4);
treap.setRoot(r);
return treap;
}

std::pair<Treap, Treap> createTreapPair() {
std::cout << "\n\ncreateTreapPair() called.\n";
Treap treap1, treap2;
std::shared_ptr<Treap::Node> r = std::make_shared<Treap::Node>(11);
treap1.setRoot(r);
treap2.setRoot(r);
return std::make_pair(treap1, treap2);
}

int main() {
const Treap treap = createTreap();
treap.display(); // Works fine, r != nullptr.

const std::pair<Treap, Treap> treapPair = createTreapPair();
treapPair.first.display(); // r is nullptr!
treapPair.second.display(); // r is nullptr!

std::cin.get();
}

如何修复上面的代码使得 rtreapPair.first.display(); treapPair.second.display(); 之后不会转向 nullptr ? r类型为 std::make_shared<Treap::Node>在两个createTreap()createTreapPair() ,那么为什么 r = std::dynamic_pointer_cast<Node>(root);Treap::display() 中将 r 变为 nullptr ?在 createTreapPair() 之后?

最佳答案

@IgorTandetnik 已经指出了您代码中的问题。

BinaryTree copy constructor explicitly slices away Treap::Node, and creates an instance of BinaryTree::Node that root holds on to. Then of course dynamic_cast<Treap::Node>(root) returns nullptr.

解决这个问题的一种方法是创建一个 virtual克隆一个 BinaryTree::Node 的成员函数并在 Node 的复制构造函数中使用它和 BinaryTree .

这是您的代码的更新版本:

class BinaryTree {
public:
class Node {
int value;
std::shared_ptr<Node> left = nullptr, right = nullptr, parent = nullptr;
friend class BinaryTree; friend class Treap;
public:
Node (int v) : value(v) {}
virtual ~Node() = default;
Node (const Node&);

//////////////////////////////
// New code
//////////////////////////////
virtual Node* clone() const = 0;

};
BinaryTree() : root(nullptr) {}
BinaryTree (const BinaryTree& other) : root(nullptr)
{
//////////////////////////////
// Updated code
//////////////////////////////
if ( other.root )
{
root = std::shared_ptr<Node>(other.root->clone());
}

std::cout << "BinaryTree copy constructor called.\n";
}
void setRoot (const std::shared_ptr<Node>& node) {root = node;}
protected:
std::shared_ptr<Node> root;
};

BinaryTree::Node::Node (const Node& other) : value(other.value) {
std::cout << "Node copy constructor called, value = " << value << '\n';

//////////////////////////////
// Updated code
//////////////////////////////
if (other.left) left = std::shared_ptr<Node>(other.left->clone());
if (other.right) right = std::shared_ptr<Node>(other.right->clone());
}

class Treap : public BinaryTree {
public:
class Node : public BinaryTree::Node {
int priority;
friend class Treap;
public:
Node (int value) : BinaryTree::Node(value), priority(std::rand() % 100) {}
Node (const Node& other) : BinaryTree::Node(other), priority(other.priority) {} // Treap::Node copy constructor.

//////////////////////////////
// New code
//////////////////////////////
virtual Node* clone() const
{
return new Node(*this);
}
};
void display() const {
std::shared_ptr<Node> r = std::dynamic_pointer_cast<Node>(root); // Casting from BinaryTree::Node to Treap::Node.
std::cout << "r = " << r.get() << '\n';
if (root) std::cout << "Root exists and has value " << root->value << ".\n";
}
};

关于c++ - 从派生类调用的复制构造函数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33353507/

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