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javascript - 在 mongodb 中通过 _id 删除不起作用

转载 作者:行者123 更新时间:2023-11-28 05:59:34 25 4
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我最初认为创建一个与我的 mongodb 一起使用的删除函数非常简单,但我无法让它工作,并且无法在谷歌或 SO 上找到解决方案。

我正在使用 MEAN 堆栈创建一个应用程序,该堆栈使用用户和类(class),并使用示例来执行用户处理部分,以便删除功能适用于用户。当我尝试复制它以便类(class)也有一个时,我无法让它工作。

已附加我用于创建服务的所有(相关)代码。其中一些可能不需要解决问题,而是与应用程序内信息的传达方式更相关。如果还需要什么,请告诉我。

客户端代码

admin/index.controller

 function deleteCourse() {
// CourseService calls app-services/course.service to enable
// all sub-pages to call all course-functions.
CourseService.Delete(event.target.id)
.then(function(){
initController();
})
.catch(function(error){
});

}

应用程序服务/course.service

function Delete(_id) {
return $http.delete('/api/courses/' + _id).then(handleSuccess, handleError);
}

服务器端代码

server.js

app.use('/api/courses', require('./controllers/api/courses.controller.js'));

我认为错误要么出现在以下文件中,要么出现在稍稍向下的 services/course.service.js 中。

courses.controller.js

var config = require('config.json');
var express = require('express');
var router = express.Router();
var CourseService = require('services/course.service');

router.delete('/:_id', deleteCourse);

module.exports = router;


function deleteCourse(req,res) {
//Do not now why req.user.sub works ( it passes on the ID).
//Copied it from the corresponding function for User with the intention to change it to req.course.sub but that didn't work.
//Somehow req.user.sub did to let it stay. Might cause the error?

var courseID = req.user.sub;
CourseService.delete(courseID)
.then(function(){
res.sendStatus(200);
})
.catch(function (err) {
res.status(400).send(err);
});
}

services/course.service.js

var config = require('config.json');
var _ = require('lodash');
var jwt = require('jsonwebtoken');
var bcrypt = require('bcryptjs');
var Q = require('q');
var mongo = require('mongoskin');


//Connectionsstring to the mongo database, if the app is runed on openshift the connectionstring value will change.
var connectionString = "mongodb://localhost:27017/mean-stack-registration-login-example";
if(process.env.OPENSHIFT_MONGODB_DB_URL){
connectionString = process.env.OPENSHIFT_MONGODB_DB_URL + "studycontrol";
}
var db = mongo.db(connectionString, { native_parser: true });

db.bind('courses');

var service = {};
service.delete = _delete;
module.exports = service;

// this is where I think the error occurs. this is the current version of it, will include examples of what i've tried earlier below. Current version corresponds with the function for deleting users.

function _delete(_id){
var deferred = Q.defer();
db.courses.remove(
{ _id: mongo.helper.toObjectID(_id) },
function (err) {
if (err) deferred.reject(err);

deferred.resolve();
});
return deferred.promise;
}

我在上面的删除功能中尝试过的示例

// function(err) has been pretty much the same as for the delete function above for all tries. 

db.collection('courses').remove({"_id": ObjectID(_id)}, function(err)...)

db.courses.remove({"_id": "ObjectId"(_id)}, function (err)... )

db.courses.remove({"_id": "$oid":(_id)}, function(err)... )

same as above but without " " around _id, ObjectID and $oid

删除services/user.service.js中用户的功能以进行比较

var config = require('config.json');
var _ = require('lodash');
var jwt = require('jsonwebtoken');
var bcrypt = require('bcryptjs');
var Q = require('q');
var mongo = require('mongoskin');


//Connects to the database with diffrent connectionstring based on if you connect localy or in openshift
var connectionString = "mongodb://localhost:27017/mean-stack-registration-login-example";
if(process.env.OPENSHIFT_MONGODB_DB_URL){
connectionString = process.env.OPENSHIFT_MONGODB_DB_URL + "studycontrol";
}
var db = mongo.db(connectionString, { native_parser: true });

db.bind('users');

var service = {};
service.delete = _delete;
module.exports = service;

//Deletes the user form the database based on ID.
function _delete(_id) {
var deferred = Q.defer();

db.users.remove(
{ _id: mongo.helper.toObjectID(_id) },
function (err) {
if (err) deferred.reject(err);
deferred.resolve();
});
return deferred.promise;
}

编辑一直在尝试Sundar和anwerjunaid的建议,并决定使用一些console.log来尝试弄清楚发生了什么。

下面是我尝试过的一个示例以及我得到的日志

db.courses.remove(
{ "_id": _id},
function (err) {
if (err) deferred.reject(err);
deferred.resolve();
console.log('inside')
console.log(deferred);
});
console.log('outside')
console.log(deferred)
return deferred.promise;


outside
defer {
promise: { state: 'pending' },
resolve: [Function],
fulfill: [Function],
reject: [Function],
notify: [Function] }
inside
defer {
promise: { state: 'fulfilled', value: undefined },
resolve: [Function],
fulfill: [Function],
reject: [Function],
notify: [Function] }

这是否意味着它在 db.courses.remove 完成之前执行 return.deferred.promise ?这可能是导致错误的原因吗?

最佳答案

您还可以尝试使用 ObjectId 类型:

var ObjectId = require('mongoose').Types.ObjectId;
var query = { _id: new ObjectId(id) }; // Pass string Id here

现在使用带有查询的删除此处

db.collection('courses').remove(query, function(err, result){
//
})

关于javascript - 在 mongodb 中通过 _id 删除不起作用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37386331/

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