c++ - 找不到 vector 使用中的 fatal error

Question

我一直在尝试将两个数字作为字符串读取，将它们转换为 int vector ，然后将它们相加用于我在学校的实验室。我已经运行我的代码来发现这个错误:

Debug Assertion Failed!

Program: C:\windows\SYSTEM32\MSVCP140D.dll File: c:\program files (x86)\microsoft visual studio 14.0\vc\include\xstring Line: 1681

Expression: vector subscript out of range

For more information on how your program can cause an assertion failure, see the Visual C++ documentation on asserts.

(Press Retry to debug the application)

我试过重试，但它会打开另一个对话框，提示调试已到达断点，此时我无法继续调试。这是我为感兴趣的人编写的代码(Microsoft Visual Studio 编译器):

#include <iostream>
#include <vector>
#include <string>

using namespace std;

void input(string &largeString1, string &largeString2);
void convert(string largeString1, string largeString2, vector<int> &largeInt1, vector<int> &largeInt2);
int asciiToInt(char ch);
void add(vector<int> largeInt1, vector<int> largeInt2, vector<int> &finalInt);
void output(const vector<int> finalInt);

int main()
{
    string largeString1;
    string largeString2;
    vector<int> largeInt1(12, 0);
    vector<int> largeInt2(12, 0);
    vector<int> finalInt(13, 0);

    for (int i = 0; i < 4; i++)
    {
        input(largeString1, largeString2);
        convert(largeString1, largeString2, largeInt1, largeInt2);
        add(largeInt1, largeInt2, finalInt);
        output(finalInt);
    }

    system("pause");

    return 0;
}
void input(string &largeString1, string &largeString2)
{
    cout << "Input:" << endl << endl;
    cin >> largeString1;
    cin >> largeString2;
}
void convert(string largeString1, string largeString2, vector<int> &largeInt1, vector<int> &largeInt2)
{
    int size1 = size(largeString1);
    int size2 = size(largeString2);
    for (int i = 0; i < 12; i++)
    {
        int dynamicsize1 = size1 - i;
        largeInt1[11 - i] = asciiToInt(largeString1[dynamicsize1 ]);
    }
    for (int j = 0; j < 12; j++)
    {
        int dynamicsize2 = size2 - j;
        largeInt2[11 - j] = asciiToInt(largeString2[dynamicsize2 ]);
    }
}
int asciiToInt(char ch)
{
    return (ch - '0');
}
void add(vector<int> largeInt1, vector<int> largeInt2, vector<int> &finalInt)
{
    for (int i = 0; i < 13; i++)
    {
        finalInt[12 - i] = largeInt1[11 - i] + largeInt2[11 - i];
    }
}
void output(const vector<int> finalInt)
{
    cout << endl << "Output:" << endl << endl << "The sum is: ";
    for (int i = 0; i < 13; i++)
    {
        cout << finalInt[i];
    }
}

Answer 1

我相信这是您正在寻找的错误:

void add(vector<int> largeInt1, vector<int> largeInt2, vector<int> &finalInt)
{
    for (int i = 0; i < 13; i++)
    {
        finalInt[12 - i] = largeInt1[11 - i] + largeInt2[11 - i];
    }
}

请注意 largeInt1 和 largeInt2 的大小为 12。但是，当 i 达到 12 时，您得到 -1 索引

finalInt[0] = largeInt1[-1] + largeInt2[-1];