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c++ - 在 C++ 中对数组进行二进制搜索

转载 作者:行者123 更新时间:2023-11-28 05:52:44 24 4
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我的二进制搜索总是返回零,我不确定为什么。也许我错误地传递了我的论点?或者也许我没有正确归还它?我不太确定出了什么问题,如果有人能解释我如何返回我想要的值而不是零,谢谢。我的数组中充满了我没有包含那部分代码的单词,因为它是由一个文件填充的。我没有输入第一个词,所以我不应该得到零。我尝试了多个单词。

     using namespace std;
#include <iostream>
#include <fstream>
#include <string>


//function prototypes
void selectionSort(string[], int);
int binarySearch(string[], int, string);

int main()
{
int open;
int name[8];
ifstream inputFile;
string filename;
int i = 0;
int size = 1024;
int newSize;
string exit;
string words[1024];
string word;
string newArray[1024];
string search;
int results;
string createdFile;
int startScan, minIndex, minValue;
//newArray[0]="This";


cout << "Please Enter the Filename: ";
cin >> filename;
inputFile.open(filename.c_str());
if (!inputFile) {
cout << "Your File could not be opened!";
}
else if (inputFile) {

while (i<1024) {
inputFile >> word;
//cout << i;
if (word.length()<2) { //gets rid of single character words
i++;
}
else if(inputFile.eof()) {
//cout<<newSize<<endl;
newSize=i;
//cout<< "DONE!"<<newSize;
break;
}
else{
newArray[i] = word;
i++;
//cout<<newArray[i]<<" " ;
//newSize=1;



//cout<<newSize;
}

//cout << newArray;
//i++;
}




}
inputFile.close();
//Take values stored in array and put them in another array with i number of elements

string finalArray[i];
size=i;
for(int j = 0; j<i;j++)
{
finalArray[j]=newArray[j];

//cout<<finalArray[j];
}

cout << "Your document has been sorted. " << endl;
selectionSort(finalArray, size);
cout<< "Out putting Your array"<<endl;
for (int z = 0; z<size; z++) {
cout << finalArray[z] << " ";
}

cout << "Please insert a word to search!: " << endl;
cin >> search;
results = binarySearch(finalArray, size, search);
cout << results << endl;
//results = binarySearch(finalArray, size, search);
//cout << results;
cout << "To exit press 0, or enter another word..." << endl;



}//end of main


void selectionSort(string array[], int size) {
int startScan, minIndex;
string minValue;

for (startScan = 0; startScan < (size - 1); startScan++)
{
minIndex = startScan;
minValue = array[startScan];
for (int index = startScan + 1; index <size; index++) {
if (array[index]<minValue) {
minValue = array[index];
minIndex = index;
}
}
array[minIndex] = array[startScan];
array[startScan] = minValue;

}
}


int binarySearch(string words[], int numElems, string word) {

int first = 0, //first array element
last = numElems - 1, //last array element
middle, //mid point of search
position = -1; //position of search value
bool found = false; //flag

while (!found && first == last)
{
middle = (first + last) / 2; //this finds the mid point
if (words[middle] == word) {
found = true;
position = middle;
}
else if (words[middle]> word) // if it's in the lower half
{
last = middle - 1;
}
else {
first = middle + 1; //if it's in the upper half
}
return position;

}
}//end binarySearch

最佳答案

问题是你有 return position;while里面循环,但不在任何 if/else 中 block ,所以它在第一次迭代后返回,即使它还没有找到搜索字符串。你应该把它移到循环之后,或者在 if 中进行设置 position 的 block 当它找到匹配的元素时。

另一个问题是 while条件为真。你想在 first 时继续循环等于last .实际上,这也不是正确的条件,因为如果数组只有一个元素,firstlast总是相等的,你会在测试它是否匹配之前停下来。所以正确的测试是while (first <= last) .

int binarySearch(string words[], int numElems, string word) 
{
int first = 0, //first array element
last = numElems - 1, //last array element
middle; //mid point of search

while (first <= last)
{
middle = (first + last) / 2; //this finds the mid point
if (words[middle] == word) {
return middle;
}
else if (words[middle]> word) // if it's in the lower half
{
last = middle - 1;
}
else {
first = middle + 1; //if it's in the upper half
}
}
return -1; // not found
}

关于c++ - 在 C++ 中对数组进行二进制搜索,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34886408/

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