javascript - 我希望根据字符串进行的计数输出创建一个数组

Question

我正在尝试制作下面的 JS 代码、开发和数组每个元音的个数1)A的计数2)E的计数3) 数我4) 计数 05)U计数

读取字符串代码后，生成每个元音出现的次数。但现在我需要创建一个数组来显示出现最频繁的元音

我知道这与创建变量有关

var MaximumSoFar 等...但是如何将它们拼凑在一起我遇到了问题。

/* * 要更改此模板，请选择“工具”|“模板 * 并在编辑器中打开模板。 */

function count_all() {
var str = document.getElementById('txtname').value;
var count9=0, totalvowels="";
var count2=0, totalconsonants="";
var count3=0, total_digits="";
var count4=0, totalA="";
var count5=0, totalE="";
var count6=0, totalI="";
var count7=0, totalO="";
var count8=0, totalU="";

for (var i = 0; i < str.length; i++) {
if (str.charAt(i).match(/[a-zA-Z]/) !== null) {
    if (str.charAt(i).match(/[aeiouAEIOU]/))
  {
totalvowels = totalvowels + str.charAt(i);
count9++;
}
if (str.charAt(i).match(/[bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ]/))
{
 totalconsonants = totalconsonants + str.charAt(i);
 count2++;
 }
 if (str.charAt(i).match(/[aA]/))
 {
 totalA = totalA + str.charAt(i);
 count4++;
 }

 if (str.charAt(i).match(/[eE]/))
 {
 totalE = totalE + str.charAt(i);
 count5++;
  }

 if (str.charAt(i).match(/[iI]/))
 {
 totalI = totalI + str.charAt(i);
 count6++;
  }

 if (str.charAt(i).match(/[oO]/))
 {
 totalO = totalO + str.charAt(i);
 count7++;
  }

 if (str.charAt(i).match(/[uU]/))
 {
 totalU = totalU + str.charAt(i);
 count8++;
 }

 }

 function retnum(str1) { 
 var num = str1.replace(/[^0-9]/g, ''); 
 return num; 
 }
 function count_digits(str2) {
  var num2 = str2.replace(/[^0-9]/g,"").length;
  return num2;
  }

  }
  document.getElementById('TotalU').value = count8;
  document.getElementById('TotalO').value = count7;
  document.getElementById('TotalI').value = count6;
  document.getElementById('TotalE').value = count5;
  document.getElementById('TotalA').value = count4;
  document.getElementById('consonant_counter').value = count2;
  document.getElementById('total_consonants').value = totalconsonants;
  document.getElementById('vowels').value = totalvowels;
  document.getElementById('vocount').value = count9;
  document.getElementById('digits1').value = count_digits(str);
  document.getElementById('digits2').value = retnum(str);
  }

  function clear_all()
   {
   document.getElementById('TotalU').value = "";
   document.getElementById('TotalO').value = "";
   document.getElementById('TotalI').value = "";
   document.getElementById('TotalE').value = "";
   document.getElementById('TotalA').value = "";
   document.getElementById('consonant_counts').value ="";
   document.getElementById('total_consonants').value ="";
   document.getElementById('vowels').value = "";
   document.getElementById('vcount').value = "";
   document.getElementById('digits1').value ="";
   document.getElementById('digits2').value ="";
   document.getElementById('txtname').value ="";
   document.getElementById('txtname').focus();
    }

Answer 1

为什么不做这样的事情呢？您提供字符串，它会返回一个对象，其中包含每个元音的计数？

function countVowels(str) {

    var result = {};
    result.a = 0;
    result.e = 0;
    result.i = 0;
    result.o = 0;
    result.u = 0;

    for (var i = 0, len = str.length; i < len; i++) {
        switch(str[i].toLowerCase()) {
            case "a":
                result.a = result.a + 1;
                break;
            case "e":
                result.e = result.e + 1;
                break;
            case "i":
                result.i = result.i + 1;
                break;
            case "o":
                result.o = result.o + 1;
                break;
            case "u":
                result.u = result.u + 1;
                break;
            default:
                break;
        }
    }

    return result;
}

当您返回结果对象时，您可以进行检查以查看哪个是最常出现的。