C++将迷宫存储到数组

Question

我是处理字符的初学者 - 这可能是菜鸟犯的错误。我有一个迷宫，看起来像

###################
#                 #
# * * * * *\* * * #
#                 #
# * * * * * * * * #
#                 #
###################

这个迷宫形成一个网格，左上角的坐标为 (0,0)。我试图将迷宫的每个元素存储到一个数组中进行处理。我当前的实现看起来像

// Print the world without the following spam and save it to an array
// Create array for storing the world and initialise
char world[width][height];

int i=0;
while(getline(infile, line)){
while(getline(infile, line)){
 int y=0;
 while(y<width){
  world[i][y]=line.at(y);
  cout << i << "," << y << "," << world[i][y];
  y++;
 }
i++;
if(i==height){break;}
}

cout << "backslash?:" << world[2][11] << endl;

终端的输出如下。

0,0,#0,1,#0,2,#0,3,#0,4,#0,5,#0,6,#0,7,#0,8,#0,9,#0,10,#0,11,#0,12,#0,13,#0,14,#0,15,#0,16,#0,17,#0,18,#
1,0,#1,1, 1,2, 1,3, 1,4, 1,5, 1,6, 1,7, 1,8, 1,9, 1,10, 1,11, 1,12, 1,13, 1,14, 1,15, 1,16, 1,17, 1,18,#
2,0,#2,1, 2,2,*2,3, 2,4,*2,5, 2,6,*2,7, 2,8,*2,9, 2,10,*2,11,\2,12,*2,13, 2,14,*2,15, 2,16,*2,17, 2,18,#
3,0,#3,1, 3,2, 3,3, 3,4, 3,5, 3,6, 3,7, 3,8, 3,9, 3,10, 3,11, 3,12, 3,13, 3,14, 3,15, 3,16, 3,17, 3,18,#
4,0,#4,1, 4,2,*4,3, 4,4,*4,5, 4,6,*4,7, 4,8,*4,9, 4,10,*4,11, 4,12,*4,13, 4,14,*4,15, 4,16,*4,17, 4,18,#
5,0,#5,1, 5,2, 5,3, 5,4, 5,5, 5,6, 5,7, 5,8, 5,9, 5,10, 5,11, 5,12, 5,13, 5,14, 5,15, 5,16, 5,17, 5,18,#
6,0,#6,1,#6,2,#6,3,#6,4,#6,5,#6,6,#6,7,#6,8,#6,9,#6,10,#6,11,#6,12,#6,13,# 6,14,#6,15,#6,16,#6,17,#6,18,#
backslash?: 

为什么最后的 cout 不显示反斜杠？

Answer 1

您在此声明中调换了高度和宽度:

char world[width][height];

所以你的数组的形状与你的输入不匹配。这意味着您在数组的边界之外写入(这是未定义的行为)并且可能会覆盖一些数据。