ios - 如何在 Swift 中为多个 UIActionSheet 创建通用方法

Question

我正在设置一个带有 2 个 UIButtons 的 UIViewController。每个按钮都有一个功能，该功能将显示一个带有几个选项的 UIAlertController。是否可以创建一个通用方法来避免两个函数中的代码重复？

我已经尝试创建一个参数类型为 UIAlertController 的函数，但我无法使用该参数。

我在这里创建了一个示例来向您展示我尝试重构的内容:

func showFirstMenu(){

    let actionSheet = UIAlertController(title: nil, message: nil, preferredStyle: .actionSheet)
    let cancel = UIAlertAction(title: "Cancel", style: .cancel, handler: nil)

    let optionOne = UIAlertAction(title: "Option 1", style: .default) { action in
        self.performSegue(withIdentifier: "optionOne", sender: self)
    }

    let optionTwo = UIAlertAction(title: "Option 2", style: .default) { action in
        self.performSegue(withIdentifier: "optionTwo", sender: self)
    }

    actionSheet.addAction(optionOne)
    actionSheet.addAction(optionTwo)
    actionSheet.addAction(cancel)

    if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiom.pad ){
        actionSheet.popoverPresentationController?.sourceView = self.view
        actionSheet.popoverPresentationController?.sourceRect = CGRect(x: self.view.bounds.midX, y: self.view.bounds.midY, width: 0, height: 0)
        actionSheet.popoverPresentationController?.permittedArrowDirections = []
        self.present(actionSheet, animated: true, completion: nil)
        print("Display on iPad")
    }
    else{
        self.present(actionSheet, animated: true, completion: nil)
        print("Display on iPhone")
    }
}

func showSecondMenu(){

    let actionSheet = UIAlertController(title: nil, message: nil, preferredStyle: .actionSheet)
    let cancel = UIAlertAction(title: "Cancel", style: .cancel, handler: nil)

    let optionThree = UIAlertAction(title: "Option 3", style: .default) { action in
        self.performSegue(withIdentifier: "optionThree", sender: self)
    }

    let optionFour = UIAlertAction(title: "Option 4", style: .default) { action in
        self.performSegue(withIdentifier: "optionFour", sender: self)
    }

    actionSheet.addAction(optionThree)
    actionSheet.addAction(optionFour)
    actionSheet.addAction(cancel)

    if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiom.pad ){
        actionSheet.popoverPresentationController?.sourceView = self.view
        actionSheet.popoverPresentationController?.sourceRect = CGRect(x: self.view.bounds.midX, y: self.view.bounds.midY, width: 0, height: 0)
        actionSheet.popoverPresentationController?.permittedArrowDirections = []
        self.present(actionSheet, animated: true, completion: nil)
        print("Display on iPad")
    }
    else{
        self.present(actionSheet, animated: true, completion: nil)
        print("Display on iPhone")
    }
}

有什么方法可以减少代码量吗？或者这是声明 UIActionSheet 的唯一方法？

感谢您阅读本文。

Answer 1

解决方案一:

如果您的 AlertViewController 的操作总是有 segue 来执行，您可以使用结构和可变参数显着减少重复，如下所示:

struct Option {
    var name: String
    var segueIdentifier: String
}

func configureActionSheet(options: Option...) {
    let actionSheet = UIAlertController(title: nil, message: nil, preferredStyle: .actionSheet)
    let cancel = UIAlertAction(title: "Cancel", style: .cancel, handler: nil)
    actionSheet.addAction(cancel)

    for option in options {
        let currentOption = UIAlertAction(title: option.name, style: .default) { action in
            self.performSegue(withIdentifier: option.segueIdentifier, sender: self)
        }
        actionSheet.addAction(currentOption)
    }

    if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiom.pad ){
        actionSheet.popoverPresentationController?.sourceView = self.view
        actionSheet.popoverPresentationController?.sourceRect = CGRect(x: self.view.bounds.midX, y: self.view.bounds.midY, width: 0, height: 0)
        actionSheet.popoverPresentationController?.permittedArrowDirections = []
    }

    self.present(actionSheet, animated: true, completion: nil)
}

func showMenu1() {
    let option1 = Option(name: "Option 1", segueIdentifier: "optionOne")
    let option2 = Option(name: "Option 2", segueIdentifier: "optionTwo")
    self.configureActionSheet(options: option1, option2)
}

解决方案 2:

如果您的 AlertViewController 的操作总是不同，那么您无能为力，但仍然可以避免重复，如下所示:

func configureActionSheet() -> UIAlertController {
    let actionSheet = UIAlertController(title: nil, message: nil, preferredStyle: .actionSheet)
    let cancel = UIAlertAction(title: "Cancel", style: .cancel, handler: nil)
    actionSheet.addAction(cancel)

    if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiom.pad ){
        actionSheet.popoverPresentationController?.sourceView = self.view
        actionSheet.popoverPresentationController?.sourceRect = CGRect(x: self.view.bounds.midX, y: self.view.bounds.midY, width: 0, height: 0)
        actionSheet.popoverPresentationController?.permittedArrowDirections = []
    }

    return actionSheet
}


func showFirstMenu() {
    let optionOne = UIAlertAction(title: "Option 1", style: .default) { action in
        self.performSegue(withIdentifier: "optionOne", sender: self)
    }

    let optionTwo = UIAlertAction(title: "Option 2", style: .default) { action in
        self.performSegue(withIdentifier: "optionTwo", sender: self)
    }

    let actionSheet = configureActionSheet()
    actionSheet.addAction(optionOne)
    actionSheet.addAction(optionTwo)
    self.present(actionSheet, animated: true, completion: nil)
}