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javascript - ReactJS 与 TypeScript 未渲染到 DOM

转载 作者:行者123 更新时间:2023-11-28 05:44:22 25 4
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我正在开发一个小项目,只是为了学习 ReactJS 和状态,我应该实现自己的状态处理方式。我想我已经弄清楚了,但我不明白为什么这不起作用。

我不断收到一条错误消息,提示无法读取 null 的属性“值”:

import * as React from 'react';
import * as ReactDOM from 'react-dom';
import UsernameLogic from './validation.ts';
import PasswordValidation from './passwordValidation.ts';

declare function require(prop: string): string;
require('./app.scss');

interface Props {

}

export default class App extends React.Component<Props, {}> {

public criteria1 = {
errorClass: 'errors',
errorMessage: 'You must enter a Username!',
isValid: false
}

public criteria2 = {
errorClass: 'errors',
errorMessage: 'Username must be at least 3 characters long',
isValid: false
}

public criteria3 = {
errorClass: 'approved',
errorMessage: 'Username must not have numeric characters',
isValid: true
}

public criteria4 = {
errorClass: 'errors',
errorMessage: 'Username must match existing User',
isValid: false
}

public criteria5 = {
errorClass: 'errors',
errorMessage: 'You must enter a Password!',
isValid: false
}

public criteron = [this.criteria1, this.criteria2, this.criteria3, this.criteria4, this.criteria5];





render() {
return (
<form name="loginForm" className="loginForm">
<div>
<div>
<input type="text" defaultValue="" placeholder="Username" id="usernameBox" className="inputField" onChange={UsernameLogic.validateUsername(this.criteron)}/>
</div>
<div>
<div id="R1" className={this.criteria1.errorClass}>{this.criteria1.errorMessage}</div>
<div id="R2" className={this.criteria2.errorClass}>{this.criteria2.errorMessage}</div>
<div id="R3" className={this.criteria3.errorClass}>{this.criteria3.errorMessage}</div>
<div id="R4" className={this.criteria4.errorClass}>{this.criteria4.errorMessage}</div>
</div>
<div>
<input type="password" defaultValue="" placeholder="Password" id="passwordBox" className="inputField" onChange={PasswordValidation.validatePassword(this.criteron)}/>
</div>
<div>
<div id="R5" className={this.criteria5.errorClass}>{this.criteria5.errorMessage}</div>
</div>
</div>
<input type="submit" />
</form>
);
}
}



ReactDOM.render(<App />, document.getElementById("app") );

这是我的逻辑:

export default class UsernameLogic {
constructor(public validateUsername) {
this.validateUsername = validateUsername;
}

public static validateUsername(currentState) {
let V = ((<HTMLInputElement>document.getElementById("usernameBox")).value === null) ? '': ((<HTMLInputElement>document.getElementById("usernameBox")).value) ;

if(currentState[0].isValid === false ||
currentState[1].isValid === false ||
currentState[2].isValid === false) {
this.checkFirstCriteria(V, currentState);
this.checkSecondCriteria(V, currentState);
this.checkThirdCriteria(V, currentState);
} else {
this.checkFourthCriteria(V, currentState);
}

}

static checkFirstCriteria(v, currentState) {
if(v.length > 0) {
let state: any;
return (state = [
{
errorClass: 'approved',
errorMessage: 'You must enter a Username!',
isValid: true
},
...currentState.slice(1,4)
]);
}
if(v.length === 0) {
let state: any;
return (state = [
{
errorClass: 'errors',
errorMessage: 'You must enter a Username!',
isValid: false
},
...currentState.slice(1,4)
]);
}
}

static checkSecondCriteria(v, currentState) {
if(v.length >= 3) {
let state: any;
return( state = [
...currentState.slice(0,0),
{
errorClass: 'approved',
errorMessage: 'Username must be at least 3 characters long',
isValid: true
},
...currentState.slice(2,4)
]);
}
if(v.length < 3) {
let state: any;
return ( state = [
...currentState.slice(0,0),
{
errorClass: 'errors',
errorMessage: 'Username must be at least 3 characters long',
isValid: false
},
...currentState.slice(2,4)
]);
}

}


static checkThirdCriteria(v, currentState) {
if(v = /\[0-9]/) {
let state: any;
return ( state = [
...currentState.slice(0,1),
{
errorClass: 'errors',
errorMessage: 'Username must not have numeric characters',
isValid: false
},
...currentState.slice(3,4)
]);
}
if(v != /\[0-9]/) {
let state: any;
return ( state = [
...currentState.slice(0,1),
{
errorClass: 'approved',
errorMessage: 'Username must not have numeric characters',
isValid: true
},
...currentState.slice(3,4)
]);
}
}


static checkFourthCriteria(v, currentState) {
let availableUser = ['dustin','sule', 'lakshmi'];
if(v === availableUser[0] ||
v === availableUser[1] ||
v === availableUser[2]) {
let state: any;
window.setTimeout(()=>{
return ( state = [
...currentState.slice(0,2),
{
errorClass: 'approved',
errorMessage: 'Username must match existing User',
isValid: true
},
...currentState.slice(4,4)
]);
}, 300)
} else {
let state: any;
window.setTimeout(()=>{
return ( state = [
...currentState.slice(0,2),
{
errorClass: 'errors',
errorMessage: 'Username must match existing User',
isValid: false
},
...currentState.slice(4,4)
]);
}, 300)
}

}



}

因此,如果有人需要更多信息或可以帮助我,那就太好了。它甚至不会渲染,但会以某种方式到达我的 onChange 事件。

最佳答案

该转换不在 .tsx 文件中,是吗?如果你在 TSX 内进行类似的转换,你必须这样做

document.getElementById("usernameBox") as HTMLInputElement

您还可以将事件对象传递给 validateUsername() 函数并从中获取值:

public static validateUsername(event, criterion) {
let V = event.target.value;

关于javascript - ReactJS 与 TypeScript 未渲染到 DOM,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38667605/

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