C++ getline 错误

Question

我遇到了这个错误，我无法弄清楚:

no instance of overloaded function "getline" matches the argument list argument types are: (std::istream, MyEnum)

代码

enum MyEnum // Needs to be before the struct that uses it
{
    Dog, Cat, Fish, Squirrel
};
struct MyStruct
{
    int a;
    float b;
    string c;
    MyEnum d;
};
int main()
{
    char myCString[arraySize] = { 0 };
    char myOtherCString[] = { "Yet another string" };
    int myInt[4] = { 27, 39, 0, 42 };
    string myString;
    MyStruct aStruct = { 4, 3.5, "Dogs", Dog };
    int x;
    int * pX = &x;
    array <MyStruct, arraySize> Animals;
    // Storing values in uninitialized variables
    myCString[0] = 'A';
    myString = "A third string";
    x = 4;
    for (int i = 0; i < arraySize; i++)
    {
        Animals[i].a = rand() % 10;
        Animals[i].b = rand() % 100 / 100.0;
        Animals[i].c = MyEnum(rand() % 4);
        cout << "Enter a name: ";
        getline(cin, Animals[i].d);
    }

Answer 1

您可能希望在 Animals[i].c 中获取输入，因为 c 是 string，而 d 不是。

此外，您可能想将 MyEnum(rand() % 4); 分配给 Animals[i].d

for (int i = 0; i < arraySize; i++)
{
    Animals[i].a = rand() % 10;
    Animals[i].b = rand() % 100 / 100.0;
    Animals[i].c = MyEnum(rand() % 4);
    //        ^^^
    // Change it to Animals[i].d
    cout << "Enter a name: ";
    getline(cin, Animals[i].d);
    //                     ^^^
    // Change it to Animals[i].c
}

这只是一种糟糕的命名风格，你应该为变量起一些有意义的名字，有了一些有意义的名字，你可能永远不会有这种错误。