c++ - 读取视频文件 "Open CV WARNING: Couldn' 时出现问题 t 读取电影文件 bird.avi"

Question

在 Xcode 中使用 C++ 完成与 opencv 相关的简单教程时，我遇到了很多问题。我无法让程序读取电影文件。请注意注释掉的部分是我测试是否存在与读取容器格式无关的问题。 IE。所有路径/图书馆等都很好。我试过 avi 容器 mp4、mov 等-这是代码:

#include <opencv2/opencv.hpp>
#include <opencv2/highgui/highgui.hpp> 
#include <iostream>
#include <unistd.h>


using namespace std;
using namespace cv;


int main(int argc, char *argv[])
{


Mat frame; // Container for each frame

string video = "bird.avi";
//    string video = "hat.jpg";

VideoCapture vid(video);
if (!vid.isOpened()) { // Check if video file was opened
    cout << "ERROR: Video file not opened...\n";
    return -1;
}

// Get fps from video inputCvCapture *input_video = cvCreateFileCapture("guitarplaying.avi");
int fps = (int)vid.get(CV_CAP_PROP_FPS); // Gets FPS from video
cout << "FPS=" << fps << endl;

// Create a window for displaying the video
namedWindow("hello"); // Creates a window
while (1) {
    if (!vid.read(frame)) { // Check end of video file
        cout << "Video file ends.\n";
        break;
    }
    // Show the frame on window
    imshow("hello", frame); // Show current frame on window
    // Wait for read next frame or key pressed
    if (waitKey(1000/fps) >= 0)
        break;
}
return 0;



}

Answer 1

替换:

string video = "bird.avi";

完整路径，例如:

string video = "c:\\samples\\bird.avi";