c++ - 继承 : call a derived class function from base class

Question

在 C++ 中可以做到这一点吗？

class Base {
     int a(Derived d) { d.b(); } 
 };

 class Derived : public Base {
    int b();
 };

我是否应该在 Base.hpp 中包含 Derived.hpp？

Answer 1

Is possible in C++ to make this?

是的，它非常简单并且是 c++ 语言中使用的基本模式(称为多态或 Template Method Pattern):

class Base {
     int a() { b(); } // Note there's no parameter needed!
// Just provide a pure virtual function declaration in the base class
protected:    
     virtual int b() = 0;

 };

 class Derived : public Base {
    int b();
 };