javascript - 使用 :data attribute as a selector to filter elements

Question

我正在尝试使用自定义数据属性通过下拉选择来过滤内容。我似乎无法让选择器正常工作，只是想知道这是否真的可行。目前正在查看https://api.jqueryui.com/data-selector/但我似乎无法让它工作。

我的 HTML:

    <div class="item-filter">
            <form>
                <select id="item-filter-select">
                  <option value="all" id="all">Show All</option>
                  <option value="clothes" id="clothes">Clothing</option>
                  <option value="jewelry" id="jewelry">Jewelry</option>
                  <option value="misc" id="misc">Miscellaneous</option>
                </select>
            </form>
        </div>

        <div class="item-display" id="item-display">

            <div class="item clothes" id="item-clothes" data-type="clothes" data-name="Sweater01" data-price="15">
                <span>Clothes</span><br>
                <a href="#" class="add-item" id="item01">Add to Cart</a>
            </div>

            <div class="item jewelry" id="item-jewelry" data-type="jewelry" data-name="Necklace01" data-price="5">
                <span>Jewelry</span><br>
                <a href="#" class="add-item" id="item02">Add to Cart</a>
            </div>

            <div class="item misc" id="item-misc" data-type="misc" data-name="PhoneCase01" data-price="10">
                <span>Misc</span><br>
                <a href="#" class="add-item" id="item03">Add to Cart</a>
            </div>

            <div class="clear"></div>
        </div>

我的JS:

    $( document ).ready(function() {
    // Handler for .ready() called.


$('#item-filter-select').change(function() {

    var clothes = $( "div:data(type, clothes)" );

    if($(this).val() === 'clothes'){
        clothes.hide();
        console.log("You selected clothes");
    }
    else if($(this).val() === 'jewelry'){
        console.log("You selected jewelry");
    }
    else if($(this).val() === 'misc'){
        console.log("You selected miscellaneous");
    } 
    else {
        console.log("You are showing all");
    }
});

});

我只想隐藏与数据类型“selected”关联的元素(我最终会使用 :not 选择器来隐藏不匹配的元素)但现在我只需要让选择器正常工作。感谢您的帮助!

Answer 1

只需直接使用选择值来定位具有正确数据属性的元素

$(document).ready(function () {
    $('#item-filter-select').on('change', function () {
        if (this.value == 'all') {
            $('.item').show();
        }else{
            var elems = $('.item[data-type="'+this.value+'"]');
            $('.item').not(elems).hide();
            elems.show();
        }
    });
});

FIDDLE

或上述的更短版本

$(document).ready(function () {
    $('#item-filter-select').on('change', function () {
        var elems = this.value == 'all' ? $('.item') : $('.item[data-type="'+this.value+'"]');
        $('.item').not(elems.show()).hide();
    });
});

FIDDLE