c++ - 在这种情况下如何找到数组中最大值的位置？

Question

#include <iostream>
#include <cmath>
#include <iomanip>

using namespace std;

class Triangle {
private:
    double area;
    double side1, side2, side3;

public:
    Triangle() {
        side1, side2, side3 = 0.0;
    }
    Triangle(double a, double b, double c) {
        side1 = a, side2 = b, side3 = c;
    }
    void setsides(double a, double b, double c) {
        side1 = a, side2 = b, side3 = c;
    }
    void calarea() {
        double s = (side1 + side2 + side3) / 2;
        area = sqrt(s*(s - side1)*(s - side2)*(s - side3));
    }
    double getarea() {
        return area;
    }

};

void main() {
    double s1, s2, s3;
    int n;
    int i;
    double max = 0;
    int maxindex = 0;
    Triangle arr[10];

    cout << "Enter the number of triangles in range 1:10: ";
    cin >> n;

    for (i = 1; i < n + 1; i++) {
        cout << "\nEnter the sides triangle " << i << ": \n";
        cin >> s1 >> s2 >> s3;
        arr[i].setsides(s1, s2, s3);
        arr[i].calarea();
        arr[i].getarea();
    }

    for (i = 1; i < n + 1; i++) {
        cout << "Area of triangle " << i << " is: " << setprecision(2) << fixed << arr[i].getarea() << "\n";
    }

    for (i = 1; i < n + 1; i++) {
        if (arr[i].getarea() > max) {
            max = arr[i].getarea();
            maxindex++;
        }
        cout << "\nThe largest area " << max << " is of triangle " << maxindex << endl;
    }
}

我知道如何获取最大值，但不知道如何“不使用algorithm 或vector”获取最大值的位置。有一个规则，如果有两个相同的最大值，我们取前一个的位置。

例如，

Area of triangle 1 is: 1.98Area of triangle 2 is: 6.00Area of triangle 3 is: 6.00Area of triangle 4 is: 2.83The largest area 6.00 is of triangle 2

Answer 1

如何找到数组中的最大值。伪代码

max = 0
foreach element
   if element > max then max = element

现在 max 有最大值。