c++ - GLUT 暂停键盘的工作

Question

我正在尝试在 GLUT c++ 上编写“Classic Snake”，但遇到了一些问题。

例如，当我的蛇向右移动时，我将目的地更改为向上，同时将其更改为向右蛇进入自身内部(我禁止将目的地从右更改为左)。我想在调用一秒钟后尝试暂停键盘功能，但我找不到任何决定。

我会在这里附上一段我的代码:

void keyboardSpecial(int k, int x, int y) {
    switch (k) {
        case GLUT_KEY_UP:
            if (snake.dest == UP || snake.dest == DOWN) break;
            else snake.dest = UP;
            break;
        case GLUT_KEY_RIGHT:
            if (snake.dest == LEFT || snake.dest == RIGHT) break;
            else snake.dest = RIGHT;
            break;
        case GLUT_KEY_DOWN:
            if (snake.dest == UP || snake.dest == DOWN) break;
            else snake.dest = DOWN;
            break;
        case GLUT_KEY_LEFT:
            if (snake.dest == LEFT || snake.dest == RIGHT) break;
            else snake.dest = LEFT;
            break;
    }
}

void timer(int) {
    //Eating and growing
    if(snake.sn[snake.size - 1].x == food.pos.x && snake.sn[snake.size - 1].y == food.pos.y) {
        food.eat();
        snake.sn[snake.size].x = snake.sn[snake.size - 1].x;
        snake.sn[snake.size].y = snake.sn[snake.size - 1].y;
        snake.size++;
    }

    //Motion
    for (int i = 1; i < snake.size; i++) {
        snake.sn[i - 1].x = snake.sn[i].x;
        snake.sn[i - 1].y = snake.sn[i].y;
    }
    if (snake.dest == RIGHT) {
        snake.sn[snake.size - 1].x++;
    }
    if (snake.dest == UP) {
        snake.sn[snake.size - 1].y--;
    }
    if (snake.dest == LEFT) {
        snake.sn[snake.size - 1].x--;
    }
    if (snake.dest == DOWN) {
        snake.sn[snake.size - 1].y++;
    }

    //Walls
    if(snake.sn[snake.size - 1].x <= 0) snake.sn[snake.size - 1].x += 640 / dx;
    if(snake.sn[snake.size - 1].x >= 640 / dx) snake.sn[snake.size - 1].x -= 640 / dx;
    if(snake.sn[snake.size - 1].y <= 0) snake.sn[snake.size - 1].y += 480 / dy;
    if(snake.sn[snake.size - 1].y >= 480 / dy) snake.sn[snake.size - 1].y -= 480 / dy;

    //Game Over
    for (int i = 0; i < snake.size - 1; i++) {
        if(snake.sn[snake.size - 1].x == snake.sn[i].x && snake.sn[snake.size - 1].y == snake.sn[i].y) {cout << "Game Over!" << endl;exit(0);}
    }

    display();
    glutTimerFunc(200 - snake.size, timer, 0);
}

Answer 1

有一个保存的时间值，您可以在键盘处理程序的开头与它进行比较，如果没有足够的时间过去，只需返回。接下来，当且仅当接受键操作时更新该值。