带有 1++ 参数的 JavaScript 递归

Question

这是多米诺骨牌游戏部分，我在递归函数中设置了三个参数，并迭代它们来分配玩家筹码。我想知道这是怎么回事，只显示前两位玩家的筹码 T.T

这是代码:

function messUp() {
fichas=[];
for (i=0;i<7;i++) {
    for (e=0;e<=i;e++) {
        fichas.push('['+i+','+e+']');
    }
} 
fichas.sort(function(){return Math.random()-0.5});
document.write(fichas+'<br/><br/>');
}
messUp();

function players(name,hand) {
this.name=name;
this.hand=hand;
}

var main=prompt("Ingrese su nombre","");

function reAsign(h,f,l) {
if (h<4) {
    toHand=[];
    for (f;f<l;f++) {
        toHand.push(fichas[f]);
        delete fichas[f];
    }
    switch (h) {
        case 0: { 
            player1=new players(main,toHand);
            l=14;
        }   
        break;
        case 1: {
            player2=new players("Player 2",toHand);
            l=21;
        }   
        break;
        case 2: {
            player3=new players("Player 3",toHand);
            l=28;
        }
        break;
        case 3: {
            player4=new players("Player 4",toHand);
        }
        break;
    }
    reAsign(h+1,f+7,l+7);
}
}
reAsign(0,0,7);

document.write(player1.name+'<br/>');
document.write(player1.hand+'<br/>');
document.write(player2.name+'<br/>');
document.write(player2.hand+'<br/>');
document.write(player3.name+'<br/>');
document.write(player3.hand+'<br/>');
document.write(player4.name+'<br/>');
document.write(player4.hand+'<br/>');

Answer 1

原因是因为这一行

reAsign(h+1,f+7,l+7);

f 已经是 +7 了，因为您迭代了它。当您最后 +7 时，它会从 7 变为 14，因此它会跳过 - 所以 2 实际上是 3 的数字，然后 4 就没有了。

与l相同。

应该是:

reAsign(h+1,f,l);

function messUp() {
fichas=[];
for (i=0;i<7;i++) {
    for (e=0;e<=i;e++) {
        fichas.push('['+i+','+e+']');
    }
} 
fichas.sort(function(){return Math.random()-0.5});
document.write(fichas+'<br/><br/>');
}
messUp();

function players(name,hand) {
this.name=name;
this.hand=hand;
}

var main=prompt("Ingrese su nombre","");

function reAsign(h,f,l) {
if (h<4) {
    toHand=[];
    for (f;f<l;f++) {
        toHand.push(fichas[f]);
        //delete fichas[f];
    }
    switch (h) {
        case 0: { 
            player1=new players(main,toHand);
            l=14;
        }   
        break;
        case 1: {
            player2=new players("Player 2",toHand);
            l=21;
        }   
        break;
        case 2: {
            player3=new players("Player 3",toHand);
            l=28;
        }
        break;
        case 3: {
            player4=new players("Player 4",toHand);
        }
        break;
    }
    reAsign(h+1,f,l);
}
}
reAsign(0,0,7);

document.write(player1.name+'<br/>');
document.write(player1.hand+'<br/>');
document.write(player2.name+'<br/>');
document.write(player2.hand+'<br/>');
document.write(player3.name+'<br/>');
document.write(player3.hand+'<br/>');
document.write(player4.name+'<br/>');
document.write(player4.hand+'<br/>');