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javascript - 需要碰撞检测的 Javascript 和 Canvas "engine"

转载 作者:行者123 更新时间:2023-11-28 04:41:36 25 4
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所以,我有一个小的“四处移动和东西”引擎,目前非常原始。

每隔一段时间(基于计时器)另一个像素 (5x5) 将出现在屏幕上 - 如果您与该像素相交,我想触发一个事件。 (公平地说,该像素 (5x5) 需要大得多 :/)。

所以,这是我的 JSFiddle(给 fiddler 们): http://jsfiddle.net/neuroflux/q9APG/

这是我的 Canvas javascript:

var canvas, ctx;
var pixX = 0; //positions
var pixY = 0;
var endX = 0;
var endY = 0;
var youX = 5; //sizes
var youY = 5;
var dis = 1; //timings
var p = 0;

window.onload = function() {
init();
}

function init() {
canvas = document.getElementById('main');
ctx = canvas.getContext('2d');
setInterval(loop,40);
var pixTimer = Math.floor((Math.random() * 1000) * 10) + 1;
setInterval(addPixel, pixTimer);
document.addEventListener('keydown',function(e) {
runMove(e);
});
}

function addPixel() {
pX = Math.floor(Math.random() * 800) + 1;
pY = Math.floor(Math.random() * 600) + 1;
p++;
}

function loop() {
ctx.clearRect(0,0,canvas.width,canvas.height);
ctx.fillRect(pixX,pixY,youX,youY);
ctx.fillText(pixX + ':' + pixY, 5, 500);
if (p > 0) {
for (var a = 0; a <= p; a++) {
ctx.fillRect(pX,pY,5,5);
}
}
}

function runMove(e) {
var canvas = document.getElementById('main');
ky = e.keyCode;
switch(ky) {
case 37:
endX = endX - dis;
if (pixX == endX) {

} else {
if (pixX >= 0 && pixX < canvas.width) {
moveleft = setInterval(ml,10);
function ml() { pixX--; }
} else {
pixX = 0;
}
}
return false;
case 38:
endY = endY - dis;
if (pixY == endY) {

} else {
if (pixY >= 0 && pixY < canvas.height) {
moveup = setInterval(mu,10);
function mu() { pixY--; }
}
}
return false;
case 39:
endX = endX + dis;
if (pixX == endX) {

} else {
if (pixX >= 0 && pixX < canvas.width) {
moveright = setInterval(mr,10);
function mr() { pixX++; }
}
}
return false;
case 40:
endY = endY + dis;
if (pixY == endY) {

} else {
if (pixY >= 0 && pixY < canvas.height) {
movedown = setInterval(md,10);
function md() { pixY++; }
}
}
return false;
case 80:
growing = setInterval(grow,100);
clearInterval(shrinking);
function grow() {
youX = youX + dis;
youY = youY + dis;
}
return false;
case 73:
clearInterval(shrinking);
clearInterval(growing);
return false;
case 79:
shrinking = setInterval(shrink,100);
clearInterval(growing);
function shrink() {
youX = youX - dis;
youY = youY - dis;
}
return false;
default:
return false;
}
}

我已经试过了,但遇到了问题 :((什么都不会触发):JSFiddle:http://jsfiddle.net/neuroflux/uF5kj/

Canvas 代码:

    var canvas, ctx;
var pixX = 0; //positions
var pixY = 0;
var endX = 0;
var endY = 0;
var youX = 5; //sizes
var youY = 5;
var dis = 1; //timings
var p = 0;
var pixel = new Array();

window.onload = function() {
init();
}

function init() {
canvas = document.getElementById('main');
ctx = canvas.getContext('2d');
setInterval(loop,40);
var pixTimer = Math.floor((Math.random() * 1000) * 10) + 1;
setInterval(addPixel, pixTimer);
document.addEventListener('keydown',function(e) {
runMove(e);
});
}

function addPixel() {
pX = Math.floor(Math.random() * 800) + 1;
pY = Math.floor(Math.random() * 600) + 1;
p++;
}

function loop() {
ctx.clearRect(0,0,canvas.width,canvas.height);
var bgImg = new Image();
bgImg.src = 'bg.png';
ctx.drawImage(bgImg,0,0,800,600);
ctx.fillRect(pixX,pixY,youX,youY);
ctx.fillText(pixX + ':' + pixY, 5, 500);
if (p > 0) {
for (var a = 0; a <= p; a++) {
pixel[a] = ctx.fillRect(pX,pY,5,5);
}
}
}

function checkIntersections() {
for (var x = 0; x < pixel.length; x++) {
if (pixX == pixel[x].x) { alert(0) }
}
}

function runMove(e) {
var canvas = document.getElementById('main');
ky = e.keyCode;
switch(ky) {
case 37:
endX = endX - dis;
if (pixX == endX) {

} else {
if (pixX >= 0 && pixX < canvas.width) {
moveleft = setInterval(ml,10);
function ml() { pixX--; }
} else {
pixX = 0;
}
}
return false;
case 38:
endY = endY - dis;
if (pixY == endY) {

} else {
if (pixY >= 0 && pixY < canvas.height) {
moveup = setInterval(mu,10);
function mu() { pixY--; }
}
}
checkIntersections();
return false;
case 39:
endX = endX + dis;
if (pixX == endX) {

} else {
if (pixX >= 0 && pixX < canvas.width) {
moveright = setInterval(mr,10);
function mr() { pixX++; }
}
}
checkIntersections();
return false;
case 40:
endY = endY + dis;
if (pixY == endY) {

} else {
if (pixY >= 0 && pixY < canvas.height) {
movedown = setInterval(md,10);
function md() { pixY++; }
}
}
checkIntersections();
return false;
case 80:
growing = setInterval(grow,100);
clearInterval(shrinking);
function grow() {
youX = youX + dis;
youY = youY + dis;
}
checkIntersections();
return false;
case 73:
clearInterval(shrinking);
clearInterval(growing);
return false;
case 79:
shrinking = setInterval(shrink,100);
clearInterval(growing);
function shrink() {
youX = youX - dis;
youY = youY - dis;
}
return false;
default:
return false;
}
}

最佳答案

等等,所以您只需要一个函数来查看两个矩形是否相交?

这里有一个防弹函数:

// returns true if there is any overlap
// params: x,y,w,h of two rectangles
function intersects(x1, y1, w1, h1, x2, y2, w2, h2) {
if (w2 !== Infinity && w1 !== Infinity) {
w2 += x2;
w1 += x1;
if (isNaN(w1) || isNaN(w2) || x2 > w1 || x1 > w2) return false;
}
if (y2 !== Infinity && h1 !== Infinity) {
h2 += y2;
h1 += y1;
if (isNaN(h1) || isNaN(y2) || y2 > h1 || y1 > h2) return false;
}
return true;
}

关于javascript - 需要碰撞检测的 Javascript 和 Canvas "engine",我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/6082667/

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