c++ - 覆盖另一个类的 friend 的虚拟保护方法

Question

基本上，我想以某种方式模拟友元继承，并限制它只能在特定方法内部发生。

所以本质上，这就是我想要的

class A; // Forward declaration
class Base{
   friend class A; // friend declaration so that A is able to see protected methods

   protected:
   virtual void method() {// some definition, might also be pure virtual}

}

class Derived : public Base{
     A aObj;
     void method(){//override the one in base and also gain access to aObj private members.}
     public:
     //public interface
} 


class A {
    int var;
    friend void Base::method(); 
    public:
      // public interface
}

有什么方法可以做到这一点吗？

Answer 1

这个怎么样

class Base {
   friend class A; 
   protected:
   virtual void method() = 0;
   std::tuple<int> GetAProperties(const A& a) {     
        // You can change the tuple params
        // as per your requirement.
        return std::make_tuple(a.var);
   }
}

class Derived : public Base {
    A aObj;
    void method() override {
        auto objProperties = GetAProperties(aObj);
    }
}