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c++ - 维数组 [Matrix] 练习的问题

转载 作者:行者123 更新时间:2023-11-28 04:26:08 25 4
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我们有一个方阵A = [aij],其中行数和行数都大于3。目标是:在矩阵A中找到表D [3;3]的位置,其中元素之和为最高的。通过指定最左边元素的索引来指定此位置。

此刻,我做了什么:已经写了一段代码,它创建了一个维度数组,并且所有的:C


int main() {
int n;
size_t height, weight;
cout << "Input height and weight of your matrix:" << endl;
cin >> dlina >> weight;
int **a = new int*[height];
for (int i = 0; i < height; i++)
a[i] = new int[weight];

for (int i = 0; i < height; i++)
for (int j = 0; j < weight; j++) {
cout << "Enter your matrix element: " << endl;
cin >> a[i][j];
}

for (int i = 0; i < height; i++){ //i=0

for (int j = 0; j < weight; j++) {//j=7
cout << a[i][j] << " ";
}

cout << endl;

}


for (int i = 0; i < height; i++)
delete[] a[i];
delete[] a;


cin >> n;

return 0;
}

最佳答案

一个简单的解决方案对您的代码进行最少的更改,包括我之前的评论:

#include <iostream>
using namespace std;

const int N = 3;

int sum(int * a[], size_t i, size_t j)
{
int n = 0;

for (size_t ii = i; ii != i + N; ++ii)
for (size_t jj = j; jj != j + N; ++jj)
n += a[ii][jj];

return n;
}

int main() {
size_t height, width;
cout << "Input height and width of your matrix:" << endl;
cin >> height >> width;

if ((height < N) || (width < N))
return 0;

int **a = new int*[height];
for (size_t i = 0; i < height; i++)
a[i] = new int[width];

for (size_t i = 0; i < height; i++) {
for (size_t j = 0; j < width; j++) {
cerr << "Enter your matrix element: " << i << ' ' << j << ":";
cin >> a[i][j];
}
}

int max = sum(a, 0, 0);
size_t maxi = 0, maxj = 0;

for (size_t i = 1; i <= (height - N); i++){
for (size_t j = 0; j <= (width - N); j++) {
int s = sum(a, i, j);

if (s > max) {
max = s;
maxi = i;
maxj = j;
}
}
}

cout << maxi << ' ' << maxj << " : " << max << endl;

for (size_t i = 0; i < height; i++)
delete[] a[i];

delete[] a;

return 0;
}

执行示例:

Input height and width of your matrix:
5 4
Enter your matrix element: 0 0:0
Enter your matrix element: 0 1:1
Enter your matrix element: 0 2:2
Enter your matrix element: 0 3:3
Enter your matrix element: 1 0:10
Enter your matrix element: 1 1:11
Enter your matrix element: 1 2:12
Enter your matrix element: 1 3:13
Enter your matrix element: 2 0:20
Enter your matrix element: 2 1:21
Enter your matrix element: 2 2:22
Enter your matrix element: 2 3:23
Enter your matrix element: 3 0:30
Enter your matrix element: 3 1:31
Enter your matrix element: 3 2:32
Enter your matrix element: 3 3:33
Enter your matrix element: 4 0:40
Enter your matrix element: 4 1:41
Enter your matrix element: 4 2:42
Enter your matrix element: 4 3:43
2 1 : 288

注意:这个简单的解决方案可以优化为每次 NxN 矩阵移动时不重做所有单元格的总和,我让你做......


valgrind 下执行:

==13767== Memcheck, a memory error detector
==13767== Copyright (C) 2002-2017, and GNU GPL'd, by Julian Seward et al.
==13767== Using Valgrind-3.13.0 and LibVEX; rerun with -h for copyright info
==13767== Command: ./a.out
==13767==
Input height and width of your matrix:
5 4
Enter your matrix element: 0 0:0
Enter your matrix element: 0 1:1
Enter your matrix element: 0 2:2
Enter your matrix element: 0 3:3
Enter your matrix element: 1 0:10
Enter your matrix element: 1 1:11
Enter your matrix element: 1 2:12
Enter your matrix element: 1 3:13
Enter your matrix element: 2 0:20
Enter your matrix element: 2 1:21
Enter your matrix element: 2 2:22
Enter your matrix element: 2 3:23
Enter your matrix element: 3 0:30
Enter your matrix element: 3 1:31
Enter your matrix element: 3 2:32
Enter your matrix element: 3 3:33
Enter your matrix element: 4 0:40
Enter your matrix element: 4 1:41
Enter your matrix element: 4 2:42
Enter your matrix element: 4 3:43
2 1 : 288
==13767==
==13767== HEAP SUMMARY:
==13767== in use at exit: 0 bytes in 0 blocks
==13767== total heap usage: 9 allocs, 9 frees, 22,372 bytes allocated
==13767==
==13767== All heap blocks were freed -- no leaks are possible
==13767==
==13767== For counts of detected and suppressed errors, rerun with: -v
==13767== ERROR SUMMARY: 0 errors from 0 contexts (suppressed: 6 from 3)

关于c++ - 维数组 [Matrix] 练习的问题,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54271362/

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