c++ - 我需要一些帮助来创建函数

Question

我是新手，对功能不是很好，我正在尝试解决这个问题:

16. Suppose A, B, C are arrays of integers of size [M], [N], and [M][N], respectively. The user will enter the values for the array A and B. Write a user defined function in C++ to calculate the third array C by adding the elements of A and B. If the elements have the same index number, they will be multiplied. C is calculated as the following: -

    Use A, B and C as arguments in the function.

下面是我对这个问题的尝试。

     #include<iostream>
using namespace std;

void Mix(int(&A)[], int(&B)[], int(&C)[][100], int N, int M);
//dont understand why you used Q

int main()
{
    //variable declaration
    int A[100], B[100], C[100][100], n, m, l = 0;


    //input of size of elements for first ararys
    cout << "Enter number of elements you want to insert in first array: ";
    cin >> n;
    cout << "-----------------" << endl;
    cout << "-----------------" << endl;
    cout << "Enter your elements in ascending order" << endl;
    //input the elements of the array
    for (int i = 0; i < n; i++)
    {
        cout << "Enter element " << i + 1 << ":";
        cin >> A[i];
    }
    cout << endl << endl;
    //input of size of elements for first ararys
    cout << "Enter number of elements you want to insert in second array: ";
    cin >> m;
    cout << "-----------------" << endl;
    cout << "-----------------" << endl;
    cout << "Enter your elements in descending order" << endl;
    //input the elements of the array
    for (int i = 0; i < m; i++)
    {
        cout << "Enter element " << i + 1 << ":";
        cin >> B[i];
    }

    Mix(A, B, C, n, m);

    cout << "\nThe Merged Array in Ascending Order" << endl;


    for (int i = 0; i < n; i++) {
        for (int j = 0; j < m; j++)
        {
            cout << C[i][j] << " ";
        }
        cout << "\n"; //endline never use endl its 10 times slower
    }

    system("pause");
    return 0;
}

void Mix(int(&A)[], int(&B)[], int(&C)[][100], int N, int M)
{
    // rows is the index for the B array, cols is index for A array
    int rows = 0;
    int cols = 0;
    while (rows < M) {
        while (cols < N) {
            if (rows == cols) { // remember ==
                C[rows][cols] = B[rows] * A[cols];
            }
            else {
                C[rows][cols] = B[rows] + A[cols];
            }
            cols++; // increment here
        }
        rows++; // increment here
    }
    return;
}

这是一个输出示例:

enter image description here

Answer 1

为了使C数组成为二维的，需要将其表示为C[100][100]，而不是C[200 ]。这是第一步。接下来，在您的 Mix() 函数中，您需要循环遍历 A 和 B 的每个元素(例如，两个 for 循环)。您的行随着 B 的变化而变化，您的列随着 A 的变化而变化。包括对相同索引的检查，以确定是将两个值相加还是相乘。

void Mix(int A[], int B[], int C[][], int N, int M) {
    // rows is the index for the B array, cols is index for A array
    for (int rows = 0; rows < M; rows++) {
        for (int cols = 0; cols < N; cols++) {
            if (rows == cols) { // remember ==
                C[rows][cols] = B[rows] * A[cols];
            } else {
                C[rows][cols] = B[rows] + A[cols];
            }
        }
    }
}

确保您的数组已正确定义并按行和列打印出 C 数组以符合规范。

更新:如果您想使用 while 循环，我会默认解构 for 循环并应用相同的逻辑:

void Mix(int A[], int B[], int C[][], int N, int M) {
    // rows is the index for the B array, cols is index for A array
    int rows = 0;
    int cols = 0;
    while (rows < M) {
        while (cols < N) {
            if (rows == cols) { // remember ==
                C[rows][cols] = B[rows] * A[cols];
            } else {
                C[rows][cols] = B[rows] + A[cols];
            }
            cols++; // increment here
        }
        rows++; // increment here
    }
}

我肯定会推荐 for 循环方法，因为它更紧凑，但执行完全相同的操作。