c++ - 2wd 蓝牙控制汽车无法停止的问题

Question

所以我正在为 2wd 蓝牙控制的足球车创建代码。当我向前按时，它会不停地向前移动。

我试过多次更改代码，例如:

if( val == '1') // Forward
    {
      digitalWrite(m1a, HIGH);
      digitalWrite(m1b, LOW);
      digitalWrite(m2a, HIGH);
      digitalWrite(m2b, LOW);
      delay(1);
      digitalWrite(m1a, LOW);
      digitalWrite(m2a, LOW);
    }

收件人:

if( val == '1') // Forward
    {
      digitalWrite(m1a, HIGH);
      digitalWrite(m1b, LOW);
      digitalWrite(m2a, HIGH);
      digitalWrite(m2b, LOW);
      delay(200);
      digitalWrite(m1a, LOW);
      digitalWrite(m2a, LOW);
      digitalWrite(m1b, LOW);
      digitalWrite(m2b, LOW);
    }

完整代码如下:

// Starting of Program
#include <SoftwareSerial.h>

SoftwareSerial mySerial(10,11);
int m1a = A3;
int m1b = A4;
int m2a = 3;
int m2b = A5;
char val;

void setup() 
{  
pinMode(m1a, OUTPUT);  // Digital pin 10 set as output Pin
pinMode(m1b, OUTPUT);  // Digital pin 11 set as output Pin
pinMode(m2a, OUTPUT);  // Digital pin 12 set as output Pin
pinMode(m2b, OUTPUT);  // Digital pin 13 set as output Pin
mySerial.begin(9600);
}

void loop()
{
  while (mySerial.available() > 0)
  {
  val = mySerial.read();
  mySerial.println(val);
  }

  if( val == '1') // Forward
    {
      digitalWrite(m1a, HIGH);
      digitalWrite(m1b, LOW);
      digitalWrite(m2a, HIGH);
      digitalWrite(m2b, LOW);
      delay(1);
      digitalWrite(m1a, LOW);
      digitalWrite(m2a, LOW);
    }
  else if(val == '2') // Backward
    {
      digitalWrite(m1a, LOW);
      digitalWrite(m1b, HIGH);
      digitalWrite(m2a, LOW);
      digitalWrite(m2b, HIGH); 
      delay(200);
      digitalWrite(m1a, LOW);
      digitalWrite(m1b, LOW);
      digitalWrite(m2a, LOW);
      digitalWrite(m2b, LOW); 
    }

    else if(val == '3') //Left
    {
      digitalWrite(m1a, LOW);
      digitalWrite(m1b, HIGH);
      digitalWrite(m2a, HIGH);
      digitalWrite(m2b, LOW);
      delay(200);
      digitalWrite(m1a, LOW);
      digitalWrite(m1b, LOW);
      digitalWrite(m2a, LOW);
      digitalWrite(m2b, LOW); 
    }
    else if(val == '4') //Right
    {
      digitalWrite(m1a, HIGH);
      digitalWrite(m1b, LOW);
      digitalWrite(m2a, LOW);
      digitalWrite(m2b, HIGH); 
      delay(200);
      digitalWrite(m1a, LOW);
      digitalWrite(m1b, LOW);
      digitalWrite(m2a, LOW);
      digitalWrite(m2b, LOW); 
    }

    else if(val == 'S')
    {
      digitalWrite(m1a, LOW);
      digitalWrite(m1b, LOW);
      digitalWrite(m2a, LOW);
      digitalWrite(m2b, LOW); 
      delay(1000);
      digitalWrite(m2a, HIGH);
    }
}

// End of program

没有错误按摩请帮忙....我正在使用 this app在我的手机和最后 11 行代码中，(val == 'S') 用于应用程序中的停止按钮。

我需要它只在按下按钮时移动，在没有按下任何按钮时停止。它不需要停止按钮。

Answer 1

if( val == '1') // Forward
{
  digitalWrite(m1a, HIGH);
  digitalWrite(m1b, LOW);
  digitalWrite(m2a, HIGH);
  digitalWrite(m2b, LOW);
  delay(1);
  digitalWrite(m1a, LOW);
  digitalWrite(m2a, LOW);
}

到

if( val == '1') // Forward
{
  digitalWrite(m1a, HIGH);
  digitalWrite(m1b, LOW);
  digitalWrite(m2a, HIGH);
  digitalWrite(m2b, LOW);
  delay(1);
  digitalWrite(m1a, LOW);
  digitalWrite(m2a, LOW);
  val = ' ';

}