gpt4 book ai didi

C++ WinSock2 等待客户端发送数据

转载 作者:行者123 更新时间:2023-11-28 04:15:08 28 4
gpt4 key购买 nike

我有一个多线程套接字服务器,它应该与客户端进行连续对话,所以我将我的 recv 放在 while(true) 中以保持连接一直持续到其中一侧关闭它。我遇到的问题是,当客户端没有发送任何东西时,服务器一直在尝试接收数据,最终导致它崩溃,因为它什么也没有读取,所以我想知道是否有办法让 recv 停止,直到有实际数据要接收。

这是处理客户端连接的函数的代码:

void Communicator::clientHandler(SOCKET client)
{
try
{
while (true)
{
char codeBuff[1];
recv(client, codeBuff, 1, 0);
int code = static_cast<int>(static_cast<unsigned char>(codeBuff[0]));
char lengthBuff[4];
recv(client, lengthBuff, 4, 0);
int dataLength = lengthBuff[0] << 24 | lengthBuff[1] << 16 | lengthBuff[2] << 8 | lengthBuff[3];
char* dataBuff = new char(dataLength);
recv(client, dataBuff, dataLength, 0);
dataBuff[dataLength - 1] = 0;

std::vector<char> dataVec(dataBuff, dataBuff + dataLength);
Request r = {
code,
std::time(nullptr),
dataVec
};

std::copy(dataVec.begin(), dataVec.end(), std::ostream_iterator<char>(std::cout, "")); // For debug purposes, prints infintiely

IRequestHandler* handler = nullptr;
{
std::lock_guard<std::mutex> locker(m_clientsMu);
handler = m_clients.find(client)->second;
}

if (handler->isRequestRelevant(r))
{
RequestResult res = handler->handleRequest(r);
{
std::lock_guard<std::mutex> locker(m_clientsMu);
delete[] m_clients.find(client)->second;
m_clients.find(client)->second = res.newHandler;
}
send(client, &res.response[0], res.response.size(), 0);
}
else
{
ErrorResponse res = { "Invalid request type" };
std::vector<char> packet = JsonPacketSerializer::serializeResponse(res);
send(client, &packet[0], packet.size(), 0);
}
}
}
catch (...)
{
closesocket(client);
throw;
}
}

我用来测试服务器的一些基本 python 代码:

import socket

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM, socket.IPPROTO_TCP)
s.connect(('127.0.0.1', 8080))
s.send(bytes([101, 0, 0, 0, 40, 123, 34, 112, 97, 115, 115, 119, 111, 114, 100, 34, 58, 34, 49, 50, 51, 52, 53, 54, 34,
44, 34, 117, 115, 101, 114, 110, 97, 109, 101, 34, 58, 34, 116, 101, 115, 116, 34, 125]))
msg = s.recv(1024)
print(msg)

最佳答案

char* dataBuff = new char(dataLength);

这将创建一个 char,最有可能的值是dataLength & 255dataBuff 将指向那个一个 char。您分配一个 char 数组,如下所示:

char* dataBuff = new char[dataLength];

您还必须稍后释放内存:

delete[] dataBuff;

您还需要注意 recv 的返回值,即接收到的字节数(或 SOCKET_ERROR 指示错误)。

关于C++ WinSock2 等待客户端发送数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56840179/

28 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com