javascript - 在 Javascript 字符串中查找单词

Question

我有一组字符串:

s1 = 'user-1 color-class';
s2 = 'text-class user-1 color-class";
s3 = 'text-class not-user-1 color-class";
s4 = 'not-user-1 color-class";
s5 = 'not-user-1 user-1 color-class";

我想为所有包含以 player- 开头的单词的字符串返回 true 或 false。也就是说，不是作为另一个单词的一部分，而是从...开始。

对于上面的内容

s1 = 'user-1 color-class';  <-- TRUE
s2 = 'text-class user-1 color-class";  <-- TRUE
s3 = 'text-class not-user-1 color-class";  <-- FALSE
s4 = 'not-user-1 color-class";  <-- FALSE
s5 = 'not-user-1 user-1 color-class";  <-- TRUE

例如:

if (hasUserClass(string)) {           <-- boolean

此外，如何从类字符串中获取 user-X 值？

userClass = getUserClass(string);     <-- `user-3`

谢谢

这是我到目前为止所做的:

function getUserClass(element)
{
    if (! element) {
        return false;
    }

    var classes = $(element).attr('class');

    if (classes.search('user-') == -1) {
        return false;
    }

    return classes.match(/player\-\d+/gi)[0];
}


function userHasClass(element)
{
    if (! element) {
        return false;
    }

    var userClass = getUserClass(element);

    return (userClass == active_user.class);
}

但这没有考虑到必须是匹配的单词的开头。

Answer 1

这是 ES6 单行代码。

s1 = 'user-1 color-class'; //<-- TRUE
s2 = 'text-class user-1 color-class';  //<-- TRUE
s3 = 'text-class not-user-1 color-class';  //<-- FALSE
s4 = 'not-user-1 color-class';  //<-- FALSE
s5 = 'not-user-1 user-1 color-class';  //<-- TRUE

const myTest = words => words.split(" ").some( str => str.startsWith("user-") )

console.log(myTest(s1), myTest(s2) ,myTest(s3), myTest(s4), myTest(s5))