c++ - 将文件目录打印成数据结构

Question

这段代码假设读取并打印目录中的每个文件，确实如此。现在我希望能够将这些文件放入数据结构中。我选择了一个列表，输出在到达实际文件之前就被切断了。我该如何解决这个问题？

"C:/Users/deonh/Downloads/intranets/intranet1\\page99.html" - 列表中我想要的

C:/Users/deonh/Downloads/intranets/intranet1 - 我得到了什么。

#include <iostream>
#include<vector>
#include<list>
#include<map>
#include<queue>
#include<fstream>
#include<string>
#include <filesystem>
namespace fs = std::filesystem;
using namespace std;

string path = "C:/Users/deonh/Downloads/intranets/intranet1"; //This gets every single file in the directory

string path5 = "C:/Users/deonh/Downloads/intranets/intranet5";
string path7 = "C:/Users/deonh/Downloads/intranets/intranet7";


int main()
{
    list<string>pages;
    map<string, int> page;


    //Here I am printing the files to make sure the above code works.
    for (const auto& entry : fs::directory_iterator(path)) {

        std::cout << entry.path() << std::endl;
        pages.push_back(path);

    }
    for (list<string> ::iterator it = pages.begin(); it != pages.end(); it++) {
        cout << *it << endl;
    }



    return 0;
}

Answer 1

您只是向列表中添加了错误的值

pages.push_back(path);

应该是

pages.push_back(entry.path().generic_string());