c++ - 为什么我的程序在我向数组输入一定数量的字母后就结束了？

Question

每次我向数组中插入一定数量的字母时，我的控制台都会立即关闭。我的代码有问题吗？另外，有没有不同的方法来计算人声的数量？

using namespace std;

int main()

{
    int i=0;
    int leng=1;
    int voc = 0;
    char seq[leng] = {};
    cout << "lets create the sequence..." << endl << "enter '*' to end sequence" << endl;

    for (i; i < leng; i++) {

        leng++;
        cin >> seq[i];
        if (seq[i] == '*') {
            break;
        }
    }

    cout << "lets check the frequency of the 5 vocals..." << endl;

    for (int z=0; z < leng; z++) {

        if (seq[z] == 'a' || seq[z] == 'e' || seq[z] == 'i' || seq[z] == 'o' || seq[z] == 'u') {
            voc+=1;
        }
    }

    leng-=2;

    cout << "so out of... " << leng << " letters, " << voc << " of them are vocals.";
}

Answer 1

我认为你的代码无法编译，原因如下:

1. 不包括 I/O 头文件
2. 不能使用变量作为数组长度
3. 没有返回
4. 等等

我按照你的方式重写了你的程序:

 #include <iostream>
 using namespace std;

 bool is_vacol(char letter)
 {
     if(letter == 'a' || letter == 'o' || letter == 'e' || letter == 'i' || letter == 'u')
         return true;
     else
         return false;
 }

 int main()
 {
     int count = 0;
     string letters;
     cout << "Please enter the letters" << endl;
     cin >> letters;
     int len = letters.size();

     cout << "lets check the frequency of the 5 vocals..." << endl;
     for(int i = 0;i < len; i++)
     {
         if(is_vacol(letters[i]))
             count++;
     }
     cout << "so out of... " << len << " letters, " << count << " of them are vocals.";
     return 0;
 }