php - 删除按钮和确认

Question

您好，我有一个工作链接可以从我的数据库中删除一行。

<a href="?action=delete&id=<? echo $id ?>" onclick="return confirm('Are you sure you want to delete?')"><strong>Delete this Case</strong></a></td>
<?php
    if($_POST['action']=="delete")
    {
         $id = $_POST['id'];

         mysql_query("DELETE FROM rmstable2 WHERE id= '$id'");
         echo("> Case # $id has been deleted as requested. To see your changes please click <a href='/martinupdate.php?id=$id'>here</a></b><br>");
    }
?>

我想要做的不是链接，而是我想要一个按钮，当按下它时它会弹出一个确认，然后如果为真则删除该行。
我不想意外删除。

<form>
    <input type="button" value="Delete this Case" onclick="return confirm('Are you sure you want to delete?')"; 
    <a href="?action=delete&id=<? echo $id ?>">
</form>

Answer 1

在你的文件的顶部试试这个:

<?php

if ($_SERVER['REQUEST_METHOD'] == 'DELETE' || ($_SERVER['REQUEST_METHOD'] == 'POST' && $_POST['_METHOD'] == 'DELETE')) {
    $id = (int) $_POST['id'];
    $result = mysql_query('DELETE FROM rmstable2 WHERE id='.$id);
    if ($result !== false) {
        // there's no way to return a 200 response and show a different resource, so redirect instead. 303 means "see other page" and does not indicate that the resource has moved.
        header('Location: http://fully-qualified-url/martinupdate.php?id='.$id, true, 303);
        exit;
    }
}

以此为形式:

<form method="POST" onsubmit="return confirm('Are you sure you want to delete this case?');">
    <input type="hidden" name="_METHOD" value="DELETE">
    <input type="hidden" name="id" value="<?php echo $id; ?>">
    <button type="submit">Delete Case</button>
</form>