c++ - 字符串和 getline 字符

Question

1. 当我运行代码时，输​​出是我的第一个和姓氏，仅此而已。
2. 我使用过 cin.clear、cin.sync 和 cin.ignore。这些似乎都不起作用。但是，当我使用cin.fail，为什么会成功？

#include<iostream>
#include<string>
using namespace std;

int main()
{
    string str_mystr;

    cout << "What is your name? ";
    getline (cin, str_mystr, '#');
    cout << "Hello " << str_mystr << '\n';
    // cin.ignore();
    cout << "What is your favorite city? ";
    getline (cin, str_mystr);
    cout << "I like " << str_mystr << '\n';
    return 0;
}

Answer 1

做你为名所做的事

#include<iostream>
#include<string>
using namespace std;

int main()
{
    string str_mystr;

    cout << "What is your name? ";
    getline (cin, str_mystr, '#');
    cout << "Hello " << str_mystr << '\n';
    // cin.ignore();
    cout << "What is your favorite city? ";
    getline (cin, str_mystr,'#');
    //                      ^^^^ 

    cout << "I like " << str_mystr << '\n';
    return 0;
}

添加“#”就可以了