c++ - VC6和模板错误

Question

我正在重载运算符 << 来为类实现类似接口(interface)的流:

template<typename T>
CAudit& operator <<  ( const T& data ) {
    audittext << data;
    return *this;
}

CAudit& operator << ( LPCSTR data ) {
    audittext << data;
    return *this;
}

模板版本无法编译，出现“ fatal error C1001:内部编译器错误(编译器文件‘msc1.cpp’，第 1794 行)”。非模板函数都可以正确编译。

这是因为 VC6s 在处理模板时存在缺陷吗？有没有办法解决这个问题？

谢谢，帕特里克

编辑:

完整的类是:

class CAudit
{
public:    
/* TODO_DEBUG : doesn't build! 
template<typename T>
CAudit& operator <<  ( const T& data ) {
    audittext << data;
    return *this;
}*/

~CAudit() { write(); }//If anything available to audit write it here

CAudit& operator << ( LPCSTR data ) {
    audittext << data;
    return *this;
}

//overload the << operator to allow function ptrs on rhs, allows "audit << data << CAudit::write;"
CAudit& operator << (CAudit & (*func)(CAudit &))
{
    return func(*this);
}

void write() {
}

//write() is a manipulator type func, "audit << data << CAudit::write;" will call this function
static CAudit& write(CAudit& audit) { 
    audit.write();
    return audit; 
}

private:
std::stringstream audittext;
};

问题出现在 operator << 的函数重载中，它用于允许 write() 被用作流操纵器:

CAudit audit
audit << "Billy" << write;

Answer 1

函数指针模板的重载对于旧的 Visual Studio 6 来说肯定是太多了。作为解决方法，您可以为您的操纵器定义一个类型并为该类型重载 operator<<。这是一些代码:

#include "stdafx.h"
#include <string>
#include <iostream>
#include <sstream>
#include <windows.h>

class CAudit {

    std::ostringstream audittext;
    void do_write() {}

public:
    ~CAudit() { do_write(); } 

    // types for manipulators
    struct Twrite {};

    // manipulators
    static Twrite write;

    // implementations of <<
    template<typename T>
        CAudit& operator <<  ( const T& data ) {
        audittext << data;
        return *this;
    }

    CAudit& operator <<  ( LPCSTR data ) {
        audittext << data;
        return *this;
    }

    CAudit& operator <<  ( Twrite& ) {
        do_write();
        return *this;
    }
};

// static member initialization
CAudit::Twrite CAudit::write;



int main(int argc, char* argv[])
{
    CAudit a;
    int i = 123;
    const char * s = "abc";

    a << i << s << CAudit::write;

    return 0;
}