c++ - 用字符随机化一个二维数组？

Question

这段代码是一个很好的解决方案，可以随机化一个二维数组并写出所有的屏幕上的符号？如果您有更好的提示或解决方案，请告诉我。

 int slumpnr;
 srand( time(0) );
 char game[3][3] = {{'O','X','A'}, {'X','A','X'}, {'A','O','O'}};

 for(int i = 0 ; i < 5 ; i++)
 {
 slumpnr = rand()%3;
 if(slumpnr == 1)
 {
 cout << " " <<game[0][0] << " | " << game[0][1] << " | " << game[0][2] << "\n";
 cout << "___|___|___\n";
 }
 else if(slumpnr == 0)
 {
 cout << " " << game[1][0] << " | " << game[1][1] << " | " << game[1][2] << "\n";
 cout << "___|___|___\n";
 }
 else if(slumpnr == 3)
 {
 cout << " " << game[2][0] << " | " << game[2][1] << " | " << game[2][2] << "\n";
 cout << "___|___|___\n";
 }
 }
 system("pause");
 }

Answer 1

您不需要 if/else 链。只需使用随机变量作为数组的索引:

int r = rand() % 3;
cout << " " <<game[r][0] << " | " << game[r][1] << " | " << game[r][2] << "\n";
cout << "___|___|___\n";

哦，我刚刚注意到你有一个从 1 到 0 和从 0 到 1 的奇怪映射。如果真的有必要(无论出于何种原因)，我会像这样实现它:

static const int mapping[] = {1, 0, 2};
int r = mapping[rand() % 3];
cout << " " <<game[r][0] << " | " << game[r][1] << " | " << game[r][2] << "\n";
cout << "___|___|___\n";

不，我没有 MSN 或其他东西，但这里有一个完整的程序可以帮助你。

#include <iostream>
#include <cstdlib>
#include <ctime>

int main()
{
    srand(time(0));
    char game[3][3] = {{'O','X','A'}, {'X','A','X'}, {'A','O','O'}};

    for (int i = 0; i < 5; ++i)
    {
        int r = rand() % 3;
        std::cout << " " <<game[r][0] << " | " << game[r][1] << " | " << game[r][2] << "\n";
        std::cout << "___|___|___\n";
    }
    system("pause");
}

但是请注意，这不是很随机，因为您只能从三个不同的可能行中进行选择。